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krati jain
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Asked: 2023-05-22T10:12:56+00:00 In:

131. How does the saturation levels limit the design? a) saturation levels decrease the flux density b) saturation levels increase the flux density c) saturation levels provides no flux density d) saturation levels provide very high flux density

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131. How does the saturation levels limit the design? a) saturation levels decrease the flux density b) saturation levels increase the flux density c) saturation levels provides no flux density d) saturation levels provide very high flux density
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    8 Answers

    1. Answer: d
      Explanation: The temperature rise is one of the limitations present in the design of
      machines. The insulating material when operated beyond the maximum temperature
      leads to the lifetime being drastically reduced.

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    3. d) saturation levels provide very high flux density

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    4. d) saturation levels provide very high flux density

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    6. Answer: d
      Explanation: The maximum allowable flux density to be used is determined by the
      saturation levels of ferromagnetic materials. The saturation levels provides high flux
      density which results in high cost.

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    7. Answer: d
      Explanation: The maximum allowable flux density to be used is determined by the
      saturation levels of ferromagnetic materials. The saturation levels provides high flux
      density which results in high cost.

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    9. Answer: d
      Explanation: The maximum allowable flux density to be used is determined by the
      saturation levels of ferromagnetic materials. The saturation levels provides high flux
      density which results in high cost.

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    10. Answer: d
      Explanation: The maximum allowable flux density to be used is determined by the
      saturation levels of ferromagnetic materials. The saturation levels provides high flux
      density which results in high cost.

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    12. Answer: c
      Explanation: ∫∫ ( 5r2

      /4) . (r2 sin θ dθ dφ), which is the integral to be evaluated. Since it is
      double integral, we need to keep only two variables and one constant compulsorily.
      Evaluate it as two integrals keeping r = 1 for the first integral and r = 2 for the second
      integral, with φ = 0→2π and θ = 0→ π. The first integral value is 80π, whereas second
      integral gives -5π. On summing both integrals, we get 75π.

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