267. Transform the vector B=yi+(x+z)j located at point (-2,6,3) into cylindrical coordinates.
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a Explanation: ρ = √(x2+y2 ) = √40 = 6.325 Φ = tan-1 (y/x) = tan-1 (-6/2) = -71.57 z = 3.
a
See lessExplanation: ρ = √(x2+y2
) = √40 = 6.325
Φ = tan-1
(y/x) = tan-1
(-6/2) = -71.57
z = 3.
A Explanation: ρ = √(x2+y2 ) = √40 = 6.325 Φ = tan-1 (y/x) = tan-1 (-6/2) = -71.57 z = 3.
A
See lessExplanation: ρ = √(x2+y2
) = √40 = 6.325
Φ = tan-1
(y/x) = tan-1
(-6/2) = -71.57
z = 3.
Answer: (6.325,-71.57,3) Explanation: ρ = √(x2+y2 ) = √40 = 6.325 Φ = tan-1 (y/x) = tan-1 (-6/2) = -71.57 z = 3.
Answer: (6.325,-71.57,3)
See lessExplanation: ρ = √(x2+y2
) = √40 = 6.325
Φ = tan-1
(y/x) = tan-1
(-6/2) = -71.57
z = 3.
Answer: a Explanation: ρ = √(x2+y2 ) = √40 = 6.325 Φ = tan-1 (y/x) = tan-1 (-6/2) = -71.57 z = 3.
Answer: a
See lessExplanation: ρ = √(x2+y2
) = √40 = 6.325
Φ = tan-1
(y/x) = tan-1
(-6/2) = -71.57
z = 3.
a) Explanation: ρ = √(x2+y2 ) = √40 = 6.325 Φ = tan-1 (y/x) = tan-1 (-6/2) = -71.57 z = 3.
a)
See lessExplanation: ρ = √(x2+y2
) = √40 = 6.325
Φ = tan-1
(y/x) = tan-1
(-6/2) = -71.57
z = 3.