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krati jain
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krati jain
Asked: May 22, 20232023-05-22T08:36:00+00:00 2023-05-22T08:36:00+00:00In: Analytics

280. Find the spherical coordinates of A(2,3,-1) a) (3.74, 105.5⁰, 56.13⁰) b) (3.74, 105.5⁰, 56.31⁰) c) (3.74, 106.5⁰, 56.13⁰) d) (3.74, 106.5⁰, 56.31⁰)

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280. Find the spherical coordinates of A(2,3,-1) a) (3.74, 105.5⁰, 56.13⁰) b) (3.74, 105.5⁰, 56.31⁰) c) (3.74, 106.5⁰, 56.13⁰) d) (3.74, 106.5⁰, 56.31⁰)
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    1. krati jain
      2023-05-22T08:36:11+00:00Added an answer on May 22, 2023 at 8:36 am

      Answer: b
      Explanation: r = √(x2+y2+z2
      ) = √14 = 3.74
      Θ = cos-1
      (z/r) = cos-1
      (-1/3.74) = 105.5⁰
      Φ = tan-1
      (y/x) = tan-1
      (3/2) = 56.31⁰

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    2. Shreya
      2023-05-24T10:50:39+00:00Added an answer on May 24, 2023 at 10:50 am

      Answer: b

      Explanation: r = √(x2+y2+z2

      ) = √14 = 3.74

      Θ = cos-1

      (z/r) = cos-1

      (-1/3.74) = 105.5⁰

      Φ = tan-1

      (y/x) = tan-1

      (3/2) = 56.31⁰.

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    3. Varsha
      2023-05-24T19:41:52+00:00Added an answer on May 24, 2023 at 7:41 pm

      Answer: b
      Explanation: r = √(x2+y2+z2
      ) = √14 = 3.74
      Θ = cos-1
      (z/r) = cos-1
      (-1/3.74) = 105.5⁰
      Φ = tan-1
      (y/x) = tan-1
      (3/2) = 56.31⁰

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    4. NISHA KASERA
      2023-05-25T16:12:32+00:00Added an answer on May 25, 2023 at 4:12 pm

      Answer: b
      Explanation: r = √(x2+y2+z2
      ) = √14 = 3.74
      Θ = cos-1
      (z/r) = cos-1
      (-1/3.74) = 105.5⁰
      Φ = tan-1
      (y/x) = tan-1
      (3/2) = 56.31⁰.

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    5. Rashi Srivastava
      2023-05-27T18:14:54+00:00Added an answer on May 27, 2023 at 6:14 pm

      Answer: b
      Explanation: r = √(x2+y2+z2

      ) = √14 = 3.74

      Θ = cos-1
      (z/r) = cos-1

      (-1/3.74) = 105.50

      Φ = tan-1
      (y/x) = tan-1

      (3/2) = 56.310.

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