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krati jain
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Asked: 2023-05-22T08:38:34+00:00 In:

283. Given B= (10/r)i+( rcos θ) j+k in spherical coordinates. Find Cartesian points at (-3,4,0) a) -2i + j b) 2i + k c) i + 2j d) –i – 2k

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283. Given B= (10/r)i+( rcos θ) j+k in spherical coordinates. Find Cartesian points at (-3,4,0) a) -2i + j b) 2i + k c) i + 2j d) –i – 2k
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    4 Answers

    1. Answer: a
      Explanation: r = √(x2+y2+z2
      ) = √25 = 5
      Θ = cos-1
      (z/r) = 1
      Φ = tan-1
      (y/x) = tan-1
      (-4/3)
      Thus, B = -2i + j.

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    3. Answer: a

      Explanation: r = √(x2+y2+z2

      ) = √25 = 5

      Θ = cos-1

      (z/r) = 1

      Φ = tan-1

      (y/x) = tan-1

      (-4/3)

      Thus, B = -2i + j.

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    4. Answer: a
      Explanation: r = √(x2+y2+z2
      ) = √25 = 5
      Θ = cos-1
      (z/r) = 1
      Φ = tan-1
      (y/x) = tan-1
      (-4/3)
      Thus, B = -2i + j.

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    6. Answer: a
      Explanation: r = √(x2+y2+z2

      ) = √25 = 5

      Θ = cos-1
      (z/r) = 1
      Φ = tan-1
      (y/x) = tan-1
      (-4/3)
      Thus, B = -2i + j.

      • 0

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