304. Find the divergence of the field, P = x2yz i + xz k
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b Explanation: Div(P) = Dx(x2yz) + Dy(0) + Dz(xz) = 2xyz + x, which is 2xyz + x. For different values of x, y, z the divergence of the field varies.
b
See lessExplanation: Div(P) = Dx(x2yz) + Dy(0) + Dz(xz) = 2xyz + x, which is 2xyz + x. For
different values of x, y, z the divergence of the field varies.
B Explanation: Div(P) = Dx(x2yz) + Dy(0) + Dz(xz) = 2xyz + x, which is 2xyz + x. For different values of x, y, z the divergence of the field varies.
B
See lessExplanation: Div(P) = Dx(x2yz) + Dy(0) + Dz(xz) = 2xyz + x, which is 2xyz + x. For different values of x, y, z the divergence of the field varies.
B Explanation: Div(P) = Dx(x2yz) + Dy(0) + Dz(xz) = 2xyz + x, which is 2xyz + x. For different values of x, y, z the divergence of the field varies.
B
See lessExplanation: Div(P) = Dx(x2yz) + Dy(0) + Dz(xz) = 2xyz + x, which is 2xyz + x. For
different values of x, y, z the divergence of the field varies.
Answer: b Explanation: Div(P) = Dx(x2yz) + Dy(0) + Dz(xz) = 2xyz + x, which is 2xyz + x. For different values of x, y, z the divergence of the field varies.
Answer: b
See lessExplanation: Div(P) = Dx(x2yz) + Dy(0) + Dz(xz) = 2xyz + x, which is 2xyz + x. For
different values of x, y, z the divergence of the field varies.
Answer: 2xyz + x Explanation: Div(P) = Dx(x2yz) + Dy(0) + Dz(xz) = 2xyz + x, which is 2xyz + x. For different values of x, y, z the divergence of the field varies.
Answer: 2xyz + x
See lessExplanation: Div(P) = Dx(x2yz) + Dy(0) + Dz(xz) = 2xyz + x, which is 2xyz + x. For
different values of x, y, z the divergence of the field varies.
b) Explanation: Div(P) = Dx(x2yz) + Dy(0) + Dz(xz) = 2xyz + x, which is 2xyz + x. For different values of x, y, z the divergence of the field varies.
b)
See lessExplanation: Div(P) = Dx(x2yz) + Dy(0) + Dz(xz) = 2xyz + x, which is 2xyz + x. For
different values of x, y, z the divergence of the field varies.