310. Find the curl of the vector and state its nature at (1,1,-0.2) F = 30 i + 2xy j + 5xz2 k a) √4.01 b) √4.02 c) √4.03 d) √4.04
310. Find the curl of the vector and state its nature at (1,1,-0.2) F = 30 i + 2xy j + 5xz2 k a) √4.01 b) √4.02 c) √4.03 d) √4.04
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Answer: d
Explanation: Curl F = -5z2
j + 2y k. At (1,1,-0.2), Curl F = -0.2 j + 2 k. |Curl F| = √(-
0.22+22
) = √4.04.
Answer: d
Explanation: Curl F = -5z2
j + 2y k. At (1,1,-0.2), Curl F = -0.2 j + 2 k. |Curl F| = √(-
0.22+22
) = √4.04.
Answer: d
Explanation: Curl F = -5z2
j + 2y k. At (1,1,-0.2), Curl F = -0.2 j + 2 k. |Curl F| = √(-
0.22+22
) = √4.04.
Answer: d
Explanation: Curl F = -5z2
j + 2y k. At (1,1,-0.2), Curl F = -0.2 j + 2 k. |Curl F| = √(-
0.22+22
) = √4.04.
Answer: d
Explanation: Curl F = -5z2
j + 2y k. At (1,1,-0.2), Curl F = -0.2 j + 2 k. |Curl F| = √(-
0.22+22
) = √4.04.