311. Is the vector is irrotational. E = yz i + xz j + xy k
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a Explanation: Curl E = i(Dy(xy) – Dz(xz)) – j (Dx(xy) – Dz(yz)) + k(Dx(xz) – Dy(yz)) = i(x – x) – j(y – y) + k(z – z) = 0 Since the curl is zero, the vector is irrotational or curl-free.
a
See lessExplanation: Curl E = i(Dy(xy) – Dz(xz)) – j (Dx(xy) – Dz(yz)) + k(Dx(xz) – Dy(yz)) =
i(x – x) – j(y – y) + k(z – z) = 0
Since the curl is zero, the vector is irrotational or curl-free.
A Explanation: Curl E = i(Dy(xy) –Dz(xz)) – j (Dx(xy) – Dz(yz)) + k(Dx(xz)Dy(yz)) =i(x – x) – j(y – y) + k(z – z) =0Since the curl is zero, the vector is irrotational or curl-free.
A
See lessExplanation: Curl E = i(Dy(xy) –Dz(xz)) – j (Dx(xy) – Dz(yz)) + k(Dx(xz)Dy(yz)) =i(x – x) – j(y – y) + k(z – z) =0Since the curl is zero, the vector is irrotational or curl-free.
A Explanation: Curl E = i(Dy(xy) – Dz(xz)) – j (Dx(xy) – Dz(yz)) + k(Dx(xz) – Dy(yz)) = i(x – x) – j(y – y) + k(z – z) = 0 Since the curl is zero, the vector is irrotational or curl-free.
A
See lessExplanation: Curl E = i(Dy(xy) – Dz(xz)) – j (Dx(xy) – Dz(yz)) + k(Dx(xz) – Dy(yz)) =
i(x – x) – j(y – y) + k(z – z) = 0
Since the curl is zero, the vector is irrotational or curl-free.
Answer: a Explanation: Curl E = i(Dy(xy) – Dz(xz)) – j (Dx(xy) – Dz(yz)) + k(Dx(xz) – Dy(yz)) = i(x – x) – j(y – y) + k(z – z) = 0 Since the curl is zero, the vector is irrotational or curl-free.
Answer: a
See lessExplanation: Curl E = i(Dy(xy) – Dz(xz)) – j (Dx(xy) – Dz(yz)) + k(Dx(xz) – Dy(yz)) =
i(x – x) – j(y – y) + k(z – z) = 0
Since the curl is zero, the vector is irrotational or curl-free.
a) Explanation: Curl E = i(Dy(xy) – Dz(xz)) – j (Dx(xy) – Dz(yz)) + k(Dx(xz) – Dy(yz)) = i(x – x) – j(y – y) + k(z – z) = 0 Since the curl is zero, the vector is irrotational or curl-free.
a)
See lessExplanation: Curl E = i(Dy(xy) – Dz(xz)) – j (Dx(xy) – Dz(yz)) + k(Dx(xz) – Dy(yz)) = i(x – x) – j(y – y) + k(z – z) = 0
Since the curl is zero, the vector is irrotational or curl-free.