313. Find the curl of the vector A = yz i + 4xy j + y k a) xi + j + (4y – z)k b) xi + yj + (z – 4y)k c) i + j + (4y – z)k d) i + yj + (4y – z)k
313. Find the curl of the vector A = yz i + 4xy j + y k a) xi + j + (4y – z)k b) xi + yj + (z – 4y)k c) i + j + (4y – z)k d) i + yj + (4y – z)k
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Answer: d
Explanation: Curl A = i(Dy(y) – Dz(0)) – j (Dx(0) – Dz(yz)) + k(Dx(4xy) – Dy(yz)) =
i + y j + (4y – z)k.
d) i + yj + (4y – z)k
Answer: d
Explanation: Curl A = i(Dy(y) – Dz(0)) – j (Dx(0) – Dz(yz)) + k(Dx(4xy) – Dy(yz)) =
i + y j + (4y – z)k.
d) i + yj + (4y – z)k
Answer: d
Explanation: Curl A = i(Dy(y) – Dz(0)) – j (Dx(0) – Dz(yz)) + k(Dx(4xy) – Dy(yz)) =
i + y j + (4y – z)k.
Answer: d
Explanation: Curl A = i(Dy(y) – Dz(0)) – j (Dx(0) – Dz(yz)) + k(Dx(4xy) – Dy(yz)) =
i + y j + (4y – z)k.