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krati jain
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Asked: 2023-05-22T09:10:10+00:00 In:

316. An electric field is given as E = 6y2z i + 12xyz j + 6xy2 k. An incremental path is given by dl = -3 i + 5 j – 2 k mm. The work done in moving a 2mC charge along the path if the location of the path is at p(0,2,5) is (in Joule) a) 0.64 b) 0.72 c) 0.78 d) 0.80

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316. An electric field is given as E = 6y2z i + 12xyz j + 6xy2 k. An incremental path is given by dl = -3 i + 5 j – 2 k mm. The work done in moving a 2mC charge along the path if the location of the path is at p(0,2,5) is (in Joule) a) 0.64 b) 0.72 c) 0.78 d) 0.80
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    1. 316. An electric field is given as E = 6y2z i + 12xyz j + 6xy2 k. An incremental
      path is given by dl = -3 i + 5 j – 2 k mm. The work done in moving a 2mC charge
      along the path if the location of the path is at p(0,2,5) is (in Joule)
      a) 0.64
      b) 0.72
      c) 0.78
      d) 0.80

       

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    3. Answer: b

      Explanation: W = -Q E.dl

      W = -2 X 10-3 X (6y2z i + 12xyz j + 6xy2 k) . (-3 i + 5 j -2 k)

      At p(0,2,5), W = -2(-18.22.5) X 10-3 = 0.72 J.

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    4. Answer: b
      Explanation: W = -Q E.dl
      W = -2 X 10-3 X (6y2z i + 12xyz j + 6xy2 k) . (-3 i + 5 j -2 k)
      At p(0,2,5), W = -2(-18.22.5) X 10-3 = 0.72 J.

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    6. Answer: b
      Explanation: W = -Q E.dl
      W = -2 X 10-3 X (6y2z i + 12xyz j + 6xy2 k) . (-3 i + 5 j -2 k)
      At p(0,2,5), W = -2(-18.22.5) X 10-3 = 0.72 J.

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    7. Answer: b
      Explanation: W = -Q E.dl
      W = -2 X 10-3 X (6y2z i + 12xyz j + 6xy2 k) . (-3 i + 5 j -2 k)
      At p(0,2,5), W = -2(-18.22.5) X 10-3 = 0.72 J.

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