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krati jain
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krati jain
Asked: May 22, 20232023-05-22T10:21:12+00:00 2023-05-22T10:21:12+00:00In: Analytics

330. Compute the Gauss law for D= 10ρ3 /4 i, in cylindrical coordinates with ρ= 4m, z=0 and z=5. a) 6100 π b) 6200 π c) 6300 π d) 6400 π

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330. Compute the Gauss law for D= 10ρ3 /4 i, in cylindrical coordinates with ρ= 4m, z=0 and z=5. a) 6100 π b) 6200 π c) 6300 π d) 6400 π
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    7 Answers

    1. krati jain
      2023-05-22T10:33:40+00:00Added an answer on May 22, 2023 at 10:33 am

      Answer: d
      Explanation: ∫∫ D.ds = ∫∫ (10ρ3
      /4).(ρ dφ dz), which is the integral to be evaluated. Put ρ =
      4m, z = 0→5 and φ = 0→2π, the integral evaluates to 6400π.

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    2. NISHA KASERA
      2023-05-25T16:47:20+00:00Added an answer on May 25, 2023 at 4:47 pm

      Answer: d
      Explanation: ∫∫ D.ds = ∫∫ (10ρ3
      /4).(ρ dφ dz), which is the integral to be evaluated. Put ρ =
      4m, z = 0→5 and φ = 0→2π, the integral evaluates to 6400π.

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    3. sonam chaudhary
      2023-05-26T06:53:11+00:00Added an answer on May 26, 2023 at 6:53 am

      d) 6400 π

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    4. nazia
      2023-05-26T09:41:51+00:00Added an answer on May 26, 2023 at 9:41 am

      Answer: d
      Explanation: ∫∫ D.ds = ∫∫ (10ρ3
      /4).(ρ dφ dz), which is the integral to be evaluated. Put ρ =
      4m, z = 0→5 and φ = 0→2π, the integral evaluates to 6400π.

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    5. Rashi Srivastava
      2023-05-28T03:29:36+00:00Added an answer on May 28, 2023 at 3:29 am

      Answer: d
      Explanation: ∫∫ D.ds = ∫∫ (10ρ3

      /4).(ρ dφ dz), which is the integral to be evaluated. Put ρ =

      4m, z = 0→5 and φ = 0→2π, the integral evaluates to 6400π.

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    6. Mohan
      2023-05-30T08:45:38+00:00Added an answer on May 30, 2023 at 8:45 am

      6400 π

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    7. Amarjit DEBBARMA
      2023-06-03T07:21:06+00:00Added an answer on June 3, 2023 at 7:21 am

      Answer: d
      Explanation: ∫∫ D.ds = ∫∫ (10ρ3
      /4).(ρ dφ dz), which is the integral to be evaluated. Put ρ =
      4m, z = 0→5 and φ = 0→2π, the integral evaluates to 6400π.

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