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Answer: c
Explanation: ∫∫ ( 5r2
/4) . (r2 sin θ dθ dφ), which is the integral to be evaluated. Since it is
double integral, we need to keep only two variables and one constant compulsorily.
Evaluate it as two integrals keeping r = 1 for the first integral and r = 2 for the second
integral, with φ = 0→2π and θ = 0→ π. The first integral value is 80π, whereas second
integral gives -5π. On summing both integrals, we get 75π.
Answer: c
Explanation: ∫∫ ( 5r2/4) . (r2 sin θ dθ dφ), which is the integral to be evaluated. Since it is double integral, we need to keep only two variables and one constant compulsorily. Evaluate it as two integrals keeping r = 1 for the first integral and r = 2 for the second integral, with φ = 0→2π and θ = 0→ π. The first integral value is 80π, whereas secondintegral gives -5π. On summing both integrals, we get 75π.
Answer: c
Explanation: ∫∫ ( 5r2
/4) . (r2 sin θ dθ dφ), which is the integral to be evaluated. Since it is
double integral, we need to keep only two variables and one constant compulsorily.
Evaluate it as two integrals keeping r = 1 for the first integral and r = 2 for the second
integral, with φ = 0→2π and θ = 0→ π. The first integral value is 80π, whereas second
integral gives -5π. On summing both integrals, we get 75π
c) 75π
Answer: c
Explanation: ∫∫ ( 5r2
/4) . (r2 sin θ dθ dφ), which is the integral to be evaluated. Since it is
double integral, we need to keep only two variables and one constant compulsorily.
Evaluate it as two integrals keeping r = 1 for the first integral and r = 2 for the second
integral, with φ = 0→2π and θ = 0→ π. The first integral value is 80π, whereas second
integral gives -5π. On summing both integrals, we get 75π.
Answer: c
Explanation: ∫∫ ( 5r2
/4) . (r2 sin θ dθ dφ), which is the integral to be evaluated. Since it is
double integral, we need to keep only two variables and one constant compulsorily.
Evaluate it as two integrals keeping r = 1 for the first integral and r = 2 for the second
integral, with φ = 0→2π and θ = 0→ π. The first integral value is 80π, whereas second
integral gives -5π. On summing both integrals, we get 75π.