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krati jain
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Asked: 2023-05-22T15:45:24+00:00 In:

381. The divergence theorem value for the function x2 + y2 + z2 at a distance of one unit from the origin is a) 0 b) 1 c) 2 d) 3

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381. The divergence theorem value for the function x2 + y2 + z2 at a distance of one unit from the origin is a) 0 b) 1 c) 2 d) 3
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    4 Answers

    1. Answer: d
      Explanation: Div (F) = 2x + 2y + 2z. The triple integral of the divergence of the function is
      ∫∫∫(2x + 2y + 2z)dx dy dz, where x = 0->1, y = 0->1 and z = 0->1. On integrating, we get 3
      units.

       

      • 0

    3. Answer: d
      Explanation: Div (F) = 2x + 2y + 2z. The triple integral of the divergence of the function is
      ∫∫∫(2x + 2y + 2z)dx dy dz, where x = 0->1, y = 0->1 and z = 0->1. On integrating, we get 3
      units.

      • 0

    4. Answer: d
      Explanation: Div (F) = 2x + 2y + 2z. The triple integral of the divergence of the function is
      ∫∫∫(2x + 2y + 2z)dx dy dz, where x = 0->1, y = 0->1 and z = 0->1. On integrating, we get 3
      units.

      • 0

    6. Answer: d
      Explanation: Div (F) = 2x + 2y + 2z. The triple integral of the divergence of the function is
      ∫∫∫(2x + 2y + 2z)dx dy dz, where x = 0->1, y = 0->1 and z = 0->1. On integrating, we get 3
      units.

      • 0

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