390. Find the force of interaction between 60 stat coulomb and 37.5 stat coulomb spaced 7.5cm apart in transformer oil(εr=2.2) in 10-4 N, a) 8.15 b) 5.18 c) 1.518 d) 1.815
390. Find the force of interaction between 60 stat coulomb and 37.5 stat coulomb spaced 7.5cm apart in transformer oil(εr=2.2) in 10-4 N, a) 8.15 b) 5.18 c) 1.518 d) 1.815
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Answer: d
Explanation: 1 stat coulomb = 1/(3 X 109
) C
F = (1.998 X 1.2488 X 10-16)/(4∏ X 8.854 X 10-12 X 2.2 X (7.5 X 10-2
)
2
) = 1.815 X 10-4 N.
d) 1.815
c) 1.404
Answer: d
Explanation: 1 stat coulomb = 1/(3 X 109) C
F = (1.998 X 1.2488 X 10-16)/(4∏ X 8.854 X 10-12 X 2.2 X (7.5 X 10-2)2) = 1.815 X 10-4 N.
Answer: d
Explanation: 1 stat coulomb = 1/(3 X 109
) C
F = (1.998 X 1.2488 X 10-16)/(4∏ X 8.854 X 10-12 X 2.2 X (7.5 X 10-2
)
2
) = 1.815 X 10-4 N.