Ratna yadav
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Enlightened
Asked: 2022-06-19T21:33:58+05:30 In:

390. Find the force of interaction between 60 stat coulomb and 37.5 stat coulomb spaced 7.5cm apart in transformer oil(εr=2.2) in 10-4 N,

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390. Find the force of interaction between 60 stat coulomb and 37.5 stat coulomb spaced 7.5cm apart in transformer oil(εr=2.2) in 10-4 N,

    6 Answers

    1. Enlightened

      d Explanation: 1 stat coulomb = 1/(3 X 109 ) C F = (1.998 X 1.2488 X 10-16)/(4∏ X 8.854 X 10-12 X 2.2 X (7.5 X 10-2 ) 2 ) = 1.815 X 10-4 N.

      d
      Explanation: 1 stat coulomb = 1/(3 X 109
      ) C
      F = (1.998 X 1.2488 X 10-16)/(4∏ X 8.854 X 10-12 X 2.2 X (7.5 X 10-2
      )
      2
      ) = 1.815 X 10-4 N.

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    3. Enlightened

      D Explanation: 1 stat coulomb = 1/(3 X 109) CF = (1.998 X 1.2488 X 10-16)/(4∏ X 8.854 X 10-12 X 2.2 X (7.5 X 10-2)2) = 1.815 X 10-4 N.

      D
      Explanation: 1 stat coulomb = 1/(3 X 109) CF = (1.998 X 1.2488 X 10-16)/(4∏ X 8.854 X 10-12 X 2.2 X (7.5 X 10-2)2) = 1.815 X 10-4 N.

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    5. Explainer

      D Explanation: 1 stat coulomb = 1/(3 X 109 ) C F = (1.998 X 1.2488 X 10-16)/(4∏ X 8.854 X 10-12 X 2.2 X (7.5 X 10-2 ) 2 ) = 1.815 X 10-4 N.

      D
      Explanation: 1 stat coulomb = 1/(3 X 109
      ) C
      F = (1.998 X 1.2488 X 10-16)/(4∏ X 8.854 X 10-12 X 2.2 X (7.5 X 10-2
      )
      2
      ) = 1.815 X 10-4 N.

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    7. Enlightened

      Answer: 1.815 X 10-4 N. Explanation: 1 stat coulomb = 1/(3 X 109 ) C F = (1.998 X 1.2488 X 10-16)/(4∏ X 8.854 X 10-12 X 2.2 X (7.5 X 10-2)²) = 1.815 X 10-4 N.

      Answer: 1.815 X 10-4 N.
      Explanation: 1 stat coulomb = 1/(3 X 109
      ) C
      F = (1.998 X 1.2488 X 10-16)/(4∏ X 8.854 X 10-12 X 2.2 X (7.5 X 10-2)²)
      = 1.815 X 10-4 N.

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    9. Enlightened

      Answer: d Explanation: 1 stat coulomb = 1/(3 X 109 ) C F = (1.998 X 1.2488 X 10-16)/(4∏ X 8.854 X 10-12 X 2.2 X (7.5 X 10-2 ) 2 ) = 1.815 X 10-4 N.

      Answer: d
      Explanation: 1 stat coulomb = 1/(3 X 109
      ) C
      F = (1.998 X 1.2488 X 10-16)/(4∏ X 8.854 X 10-12 X 2.2 X (7.5 X 10-2
      )
      2
      ) = 1.815 X 10-4 N.

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    11. Enlightened

      d) Explanation: 1 stat coulomb = 1/(3 X 109) CF = (1.998 X 1.2488 X 10-16)/(4∏ X 8.854 X 10-12 X 2.2 X (7.5 X 10-2) = 1.815 X 10-4 N.

      d)
      Explanation: 1 stat coulomb = 1/(3 X 109) CF = (1.998 X 1.2488 X 10-16)/(4∏ X 8.854 X 10-12 X 2.2 X (7.5 X 10-2) = 1.815 X 10-4 N.

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