413. Find the flux density of line charge of radius (cylinder is the Gaussian surface) 2m and charge density is 3.14 units?

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d Explanation: The electric field of a line charge is given by, E = λ/(2περ), where ρ is the radius of cylinder, which is the Gaussian surface and λ is the charge density. The density D = εE = λ/(2πρ) = 3.14/(2π X 2) = 1/4 = 0.25.

d

See lessExplanation: The electric field of a line charge is given by, E = λ/(2περ), where ρ is the

radius of cylinder, which is the Gaussian surface and λ is the charge density. The

density D = εE = λ/(2πρ) = 3.14/(2π X 2) = 1/4 = 0.25.

Answer: d Explanation: The electric field of a line charge is given by, E = λ/(2περ), where ρ is the radius of cylinder, which is the Gaussian surface and λ is the charge density. The density D = εE = λ/(2πρ) = 3.14/(2π X 2) = 1/4 = 0.25.

Answer: d

See lessExplanation: The electric field of a line charge is given by, E = λ/(2περ), where ρ is the

radius of cylinder, which is the Gaussian surface and λ is the charge density. The

density D = εE = λ/(2πρ) = 3.14/(2π X 2) = 1/4 = 0.25.

d) Explanation: The electric field of a line charge is given by, E = λ/(2περ), where ρ is the radius of cylinder, which is the Gaussian surface and λ is the charge density. The density D = εE = λ/(2πρ) = 3.14/(2π X 2) = 1/4 = 0.25.

d)

See lessExplanation: The electric field of a line charge is given by, E = λ/(2περ), where ρ is the radius of cylinder, which is the Gaussian surface and λ is the charge density. The density D = εE = λ/(2πρ) = 3.14/(2π X 2) = 1/4 = 0.25.

d Explanation: The electric field of a line charge is given by, E = λ/(2περ), where ρ is the radius of cylinder, which is the Gaussian surface and λ is the charge density. The density D = εE = λ/(2πρ) = 3.14/(2π X 2) = 1/4 = 0.25.

d

Explanation: The electric field of a line charge is given by, E = λ/(2περ), where ρ is the

radius of cylinder, which is the Gaussian surface and λ is the charge density. The

density D = εE = λ/(2πρ) = 3.14/(2π X 2) = 1/4 = 0.25.

See lessExplanation: The electric field of a line charge is given by, E = λ/(2περ), where ρ is the radius of cylinder, which is the Gaussian surface and λ is the charge density. The density D = εE = λ/(2πρ) = 3.14/(2π X 2) = 1/4 = 0.25.

Explanation: The electric field of a line charge is given by, E = λ/(2περ), where ρ is the radius of cylinder, which is the Gaussian surface and λ is the charge density. The density D = εE = λ/(2πρ) = 3.14/(2π X 2) = 1/4 = 0.25.

See lessAnswer: d Explanation: The electric field of a line charge is given by, E = λ/(2περ), where ρ is the radius of cylinder, which is the Gaussian surface and λ is the charge density. The density D = εE = λ/(2πρ) = 3.14/(2π X 2) = 1/4 = 0.25.

Answer: d

radius of cylinder, which is the Gaussian surface and λ is the charge density. The

density D = εE = λ/(2πρ) = 3.14/(2π X 2) = 1/4 = 0.25.

0.25

0.25

See lessD. Explanation: The electric field of a line charge is given by, E = λ/(2περ), where ρ is the radius of cylinder, which is the Gaussian surface and λ is the charge density. The density D = εE = λ/(2πρ) = 3.14/(2π X 2) = 1/4 = 0.25.

D.