417. A point charge 2nC is located at origin. What is the potential at (1,0,0)?
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d Explanation: V = Q/(4πεr), where r = 1m V = (2 X 10-9 )/(4πε x 1) = 18 volts.
d
See lessExplanation: V = Q/(4πεr), where r = 1m
V = (2 X 10-9
)/(4πε x 1) = 18 volts.
D Explanation: V = Q/(4πεr), where r = 1m V = (2 X 10-9)/(4πε x 1) = 18 volts.
D
See lessExplanation: V = Q/(4πεr), where r = 1m
V = (2 X 10-9)/(4πε x 1) = 18 volts.
d Explanation: V = Q/(4πεr), where r = 1m V = (2 X 10-9 )/(4πε x 1) = 18 volts.
d
See lessExplanation: V = Q/(4πεr), where r = 1m
V = (2 X 10-9
)/(4πε x 1) = 18 volts.
Answer: d Explanation: V = Q/(4πεr), where r = 1m V = (2 X 10-9 )/(4πε x 1) = 18 volts.
Answer: d
See lessExplanation: V = Q/(4πεr), where r = 1m
V = (2 X 10-9
)/(4πε x 1) = 18 volts.
d) Explanation: V = Q/(4πεr), where r = 1m V = (2 X 10-9)/(4πε x 1) = 18 volts.
d)
See lessExplanation: V = Q/(4πεr), where r = 1m
V = (2 X 10-9)/(4πε x 1) = 18 volts.