419. A point charge 0.4nC is located at (2, 3, 3). Find the potential differences between (2, 3, 3)m and (-2, 3, 3)m due to the charge
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c Explanation: Vab = (Q/4πεo)(1/rA) + (1/rB), where rA and rB are position vectors rA = 1m and rB = 4m. Thus Vab = 2.7 volts.
c
See lessExplanation: Vab = (Q/4πεo)(1/rA) + (1/rB), where rA and rB are position vectors rA =
1m and rB = 4m. Thus Vab = 2.7 volts.
Answer: 2.7 Explanation: Vab = (Q/4πεo)(1/rA) + (1/rB), where rA and rB are position vectors rA = 1m and rB = 4m. Thus Vab = 2.7 volts.
Answer: 2.7
See lessExplanation: Vab = (Q/4πεo)(1/rA) + (1/rB), where rA and rB are position vectors rA =
1m and rB = 4m. Thus Vab = 2.7 volts.
c) Explanation: Vab = (Q/4πεo)(1/rA) + (1/rB), where rA and rB are position vectors rA = 1m and rB = 4m. Thus Vab = 2.7 volts.
c)
See lessExplanation: Vab = (Q/4πεo)(1/rA) + (1/rB), where rA and rB are position vectors rA = 1m and rB = 4m. Thus Vab = 2.7 volts.