420. Find the potential of V = 60sin θ/r2 at P(3,60,25)
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a Explanation: V = 60sin θ/r2 , put r = 3m, θ = 60 and φ = 25, V = 60 sin 60/32 = 5.774 volts.
a
See lessExplanation: V = 60sin θ/r2
, put r = 3m, θ = 60 and φ = 25, V = 60 sin 60/32 = 5.774 volts.
Answer: 5.774 Explanation: V = 60sin θ/r2 , put r = 3m, θ = 60 and φ = 25, V = 60 sin 60/32 = 5.774 volts.
Answer: 5.774
See lessExplanation: V = 60sin θ/r2
, put r = 3m, θ = 60 and φ = 25, V = 60 sin 60/32 = 5.774 volts.
Answer: a Explanation: V = 60sin θ/r2 , put r = 3m, θ = 60 and φ = 25, V = 60 sin 60/32 = 5.774 volts.
Answer: a
See lessExplanation: V = 60sin θ/r2
, put r = 3m, θ = 60 and φ = 25, V = 60 sin 60/32 = 5.774 volts.
a) Explanation: V = 60sin θ/r2, put r = 3m, θ = 60 and φ = 25, V = 60 sin 60/32 = 5.774 volts.
a)
See lessExplanation: V = 60sin θ/r2, put r = 3m, θ = 60 and φ = 25, V = 60 sin 60/32 = 5.774 volts.