420. Find the potential of V = 60sin θ/r2 at P(3,60,25) a) 5.774 b) 6.774 c) 7.774 d) 8.774
Gautam Khithani
Asked: April 9, 20242024-04-09T22:03:27+00:00
2024-04-09T22:03:27+00:00In: Education
420. Find the potential of V = 60sin θ/r2 at P(3,60,25) a) 5.774 b) 6.774 c) 7.774 d) 8.774
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Answer: a
Explanation: V = 60sin θ/r2
, put r = 3m, θ = 60 and φ = 25, V = 60 sin 60/32 = 5.774 volts.