421. Given E = 40xyi + 20×2 j + 2k. Calculate the potential between two points (1,-1,0) and (2,1,3)
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b Explanation: V = -∫ E.dl = -∫ (40xy dx + 20x2 dy + 2 dz), from (2,1,3) to (1,-1,0), we get Vpq on integrating from Q to P. Vpq = 106 volts.
b
See lessExplanation: V = -∫ E.dl = -∫ (40xy dx + 20×2 dy + 2 dz), from (2,1,3) to (1,-1,0), we get
Vpq on integrating from Q to P. Vpq = 106 volts.
Answer: 106 volts Explanation: V = -∫ E.dl = -∫ (40xy dx + 20x2 dy + 2 dz), from (2,1,3) to (1,-1,0), we get Vpq on integrating from Q to P. Vpq = 106 volts.
Answer: 106 volts
Explanation: V = -∫ E.dl = -∫ (40xy dx + 20×2 dy + 2 dz), from (2,1,3) to (1,-1,0), we get
See lessVpq on integrating from Q to P. Vpq = 106 volts.