421. Given E = 40xyi + 20×2 j + 2k. Calculate the potential between two points (1,-1,0) and (2,1,3). a) 105 b) 106 c) 107 d) 108
421. Given E = 40xyi + 20×2 j + 2k. Calculate the potential between two points (1,-1,0) and (2,1,3). a) 105 b) 106 c) 107 d) 108
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Answer: b
Explanation: V = -∫ E.dl = -∫ (40xy dx + 20×2 dy + 2 dz), from (2,1,3) to (1,-1,0), we get
Vpq on integrating from Q to P. Vpq = 106 volts.