A 200 bus power system has 160 PQ bus. For achieving a load flow solution by N-R in polar coordinates, the minimum number of simultaneous equation to be solved is ___________ a) 359 b) 334 c) 357 d) 345

# A 200 bus power system has 160 PQ bus. For achieving a load flow solution by N-R in polar coordinates, the minimum number of simultaneous equation to be solved is ___________ a) 359 b) 334 c) 357 d) 345

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Answer: a

Explanation: Total buses = 200

PQ buses = 160

PV buses = 200-160 = 40

Slack bus = 1

Total number of equation = (40-1)*1 + (160*2) = 359

Answer: a

a) 359

Answer: a

a) 359

Answer: a

Explanation: Total buses = 200

PQ buses = 160

PV buses = 200-160 = 40

Slack bus = 1

Total number of equation = (40-1)*1 + (160*2) = 359

Answer: a

Explanation: Total buses = 200

PQ buses = 160

PV buses = 200-160 = 40

Slack bus = 1

Total number of equation = (40-1)*1 + (160*2) = 359.

a) 359