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Virendra Yadav
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Asked: 2023-04-27T08:35:04+00:00 In:

A 200 bus power system has 160 PQ bus. For achieving a load flow solution by N-R in polar coordinates, the minimum number of simultaneous equation to be solved is ___________ a) 359 b) 334 c) 357 d) 345

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A 200 bus power system has 160 PQ bus. For achieving a load flow solution by N-R in polar coordinates, the minimum number of simultaneous equation to be solved is ___________ a) 359 b) 334 c) 357 d) 345
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    8 Answers

    1. Answer: a
      Explanation: Total buses = 200
      PQ buses = 160
      PV buses = 200-160 = 40
      Slack bus = 1
      Total number of equation = (40-1)*1 + (160*2) = 359

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    3. Answer: a

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    4. a) 359

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    6. Answer: a

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    7. a) 359

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    9. Answer: a
      Explanation: Total buses = 200
      PQ buses = 160
      PV buses = 200-160 = 40
      Slack bus = 1
      Total number of equation = (40-1)*1 + (160*2) = 359

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    10. Answer: a
      Explanation: Total buses = 200
      PQ buses = 160
      PV buses = 200-160 = 40
      Slack bus = 1
      Total number of equation = (40-1)*1 + (160*2) = 359.

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    12. a) 359

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