The rate of diffusion methane is twice that of X. The molecular mass of X is
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64.0 Explanation: Let rate of diffusion of gas x, r1 = a Therefore, rate of diffusion of methane, r2 = 2 a According to Grahams Law of Diffusion (r1r2) = (M2M1−−−√) M1 = Molecular mass of gas x M2 = Molecular mass of Methane = 16 g Therefore, (a2a) = (16M2−−−√) Squaring both the sides, (14) = (16M2)Read more
64.0
See lessExplanation:
Let rate of diffusion of gas x, r1 = a
Therefore, rate of diffusion of methane, r2 = 2 a
According to Grahams Law of Diffusion
(r1r2) = (M2M1−−−√)
M1 = Molecular mass of gas x
M2 = Molecular mass of Methane = 16 g
Therefore, (a2a) = (16M2−−−√)
Squaring both the sides, (14) = (16M2)
or, M2 = 16 × 4 = 64 g