The sulphate of a metal M contains 9.87% of M. This sulphate is isomorphous with ZnSO4.7H2O. The atomic weight of M is

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Answer: (c) 24.3 Explanation: As the given sulphate is isomorphous with ZnSO4.7H2O its formula would be MSO4.7H2O.m is the atomic weight of M, molecular weight of MSO4.7H2O = (m + 32 + 64 + 126) = (m + 222) Hence % of M= [(m)/ (m+222)] × 100 = 9.87(given) Or 100 m = (9.87 m + 222 × 9.87) Or 90.13 mRead more

Answer: (c) 24.3

See lessExplanation:

As the given sulphate is isomorphous with ZnSO

_{4}.7H_{2}O its formula would be MSO_{4}.7H_{2}O.m is the atomic weight of M, molecular weight of MSO_{4}.7H_{2}O= (m + 32 + 64 + 126) = (m + 222)

Hence % of M= [(m)/ (m+222)] × 100 = 9.87(given)

Or

100 m = (9.87 m + 222 × 9.87)

Or 90.13 m = (222 × 9.87)

Or m = (222 × 9.87)/(90.13)

= 24.3.