Which of the Pythagorean Theorem is valid in Electromagnetics? a) |dot product| + |dot product| = 1 b) |cross product| – |cross product| = 1 c) |dot product|2 + |cross product|2 = 1 d) |dot product| + |cross product| = 0

# Which of the Pythagorean Theorem is valid in Electromagnetics? a) |dot product| + |dot product| = 1 b) |cross product| – |cross product| = 1 c) |dot product|2 + |cross product|2 = 1 d) |dot product| + |cross product| = 0

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c) |dot product|2 + |cross product|2 = 1

c) |dot product|2 + |cross product|2 = 1

c) |dot product|2 + |cross product|2 = 1

c) |dot product|2 + |cross product|2 = 1

c) |dot product|

2 + |cross product|

2 = 1

Answer: c

Answer: c

|dot product|2 + |cross product|2 = 1

c) |dot product|

2 + |cross product|

2 = 1

Answer: c

Explanation: Option |dot product|2 + |cross product|2 = 1 gives |cos|2 + |sin|2 = 1, which is

the right answer.

Answer: c

Explanation: Option |dot product|2 + |cross product|2 = 1 gives |cos|2 + |sin|2 = 1, which is the right answer

(c) |dot product|^2 + |cross product|^2 = 1

c) |dot product|2 + |cross product|2 = 1

c) |dot product|

2 + |cross product|

2 = 1

Answer: c

Explanation: Option |dot product|

^{2}+ |cross product|^{2}= 1 gives |cos|^{2}+ |sin|^{2}= 1, which is the right answer.|dot product|2 + |cross product|2 = 1

|dot product|2 + |cross product|2 = 1

c) |dot product|

2 + |cross product|

2 = 1

c) |dot product|

2 + |cross product|

2 = 1

|dot product|2 + |cross product|2 = 1

c) |dot product|

2 + |cross product|

2 = 1

Answer: c

Explanation: Option |dot product|2 + |cross product|2 = 1 gives |cos|2 + |sin|2 = 1, which is

the right answer.