Find the current in a conductor with resistance 2 ohm, electric field 2 units and distance 100cm.

To find the current in a conductor, we typically either use Ohm’s Law, which is (I = frac{V}{R}) (where (I) is the current, (V) is the potential difference, and (R) is the resistance), or we consider the relationship involving the electric field if the necessary variables for Ohm’s Law aren’t directly provided.

Given:

– Resistance ((R)) = 2 ohms,

– Electric field ((E)) = 2 units (assuming standard SI units, this would be 2 N/C, as electric field strength is typically measured in newtons per coulomb or volts per meter),

– Distance ((l)) = 100 cm = 1 meter (since 100 cm = 1 m, for consistency in SI units).

First, we need to ascertain the relationship between the electric field ((E)), the distance ((l)), and how we might derive the potential difference ((V)) from these, because (V = E times l) in a uniform electric field.

Given:

[E = 2 , text{N/C}]

[l = 1 , text{m}]

[V = E times l = 2 , text{N/C} times 1 , text{m} = 2 , text{V}]

Now, applying Ohm’s Law