1. | Any signed negative binary number is recognised by its |
A. | msb |
B. | lsb |
C. | byte |
D. | nibble |
Answer» A. msb |
2. | The parameter through which 16 distinct values can be represented is known as |
A. | bit |
B. | byte |
C. | word |
D. | nibble |
Answer» C. word |
3. | The representation of octal number (532.2)8 in decimal is |
A. | (346.25)10 |
B. | (532.864)10 |
C. | (340.67)10 |
D. | (531.668)10 |
Answer» A. (346.25)10 |
4. | The decimal equivalent of the binary number (1011.011)2 is |
A. | (11.375)10 |
B. | (10.123)10 |
C. | (11.175)10 |
D. | (9.23)10 |
Answer» A. (11.375)10 |
5. | An important drawback of binary system is |
A. | it requires very large string of 1’s and 0’s to represent a decimal number |
B. | it requires sparingly small string of 1’s and 0’s to represent a decimal number |
C. | it requires large string of 1’s and small string of 0’s to represent a decimal number |
D. | it requires small string of 1’s and large string of 0’s to represent a decimal number |
Answer» A. it requires very large string of 1’s and 0’s to represent a decimal number |
6. | The decimal equivalent of the octal number (645)8 is |
A. | (450)10 |
B. | (451)10 |
C. | (421)10 |
D. | (501)10 |
Answer» C. (421)10 |
7. | The largest two digit hexadecimal number is |
A. | (fe)16 |
B. | (fd)16 |
C. | (ff)16 |
D. | (ef)16 |
Answer» C. (ff)16 |
8. | Representation of hexadecimal number (6DE)H in decimal: |
A. | 6 * 162 + 13 * 161 + 14 * 160 |
B. | 6 * 162 + 12 * 161 + 13 * 160 |
C. | 6 * 162 + 11 * 161 + 14 * 160 |
D. | 6 * 162 + 14 * 161 + 15 * 160 |
Answer» A. 6 * 162 + 13 * 161 + 14 * 160 |
9. | The quantity of double word is |
A. | 16 bits |
B. | 32 bits |
C. | 4 bits |
D. | 8 bits |
Answer» B. 32 bits |
10. | What does RTL in digital circuit design stand for? |
A. | register transfer language |
B. | register transfer logic |
C. | register transfer level |
D. | resistor-transistor logic |
Answer» C. register transfer level |
11. | RTL is a design abstraction of what kind of circuit? |
A. | asynchronous digital circuit |
B. | synchronous digital circuit |
C. | asynchronous sequential circuit |
D. | analog circuit |
Answer» B. synchronous digital circuit |
12. | RTL is used in HDL to create what level of representations in the circuit? |
A. | high-level |
B. | low-level |
C. | mid-level |
D. | same level |
Answer» A. high-level |
13. | RTL mainly focuses on describing the flow of signals between |
A. | logic gates |
B. | registers |
C. | clock |
D. | inverter |
Answer» B. registers |
14. | Which flip-flop is usually used in the implementation of the registers? |
A. | d flip-flop |
B. | s-r flip-flop |
C. | t flip-flop |
D. | j-k flip-flop |
Answer» A. d flip-flop |
15. | Which of the following tool performs logic optimization? |
A. | simulation tool |
B. | synthesis tool |
C. | routing tool |
D. | rtl compiler |
Answer» B. synthesis tool |
16. | Hold time is the time needed for the data to after the edge of the clock is triggered. |
A. | decrease |
B. | increase |
C. | remain constant |
D. | negate |
Answer» C. remain constant |
17. | Simulator enters in which phase after the initialization phase? |
A. | execution phase |
B. | compilation phase |
C. | elaboration phase |
D. | simulation phase |
Answer» A. execution phase |
18. | All input of NOR as low produces result as |
A. | low |
B. | mid |
C. | high |
D. | floating |
Answer» C. high |
19. | In RTL NOR gate, the output is at logic 1 only when all the inputs are at |
A. | logic 0 |
B. | logic 1 |
C. | +10v |
D. | floating |
Answer» A. logic 0 |
20. | The role of the is to convert the collector current into a voltage in RTL. |
A. | collector resistor |
B. | base resistor |
C. | capacitor |
D. | inductor |
Answer» A. collector resistor |
21. | The limitations of the one transistor RTL NOR gate are overcome by |
A. | two-transistor rtl implementation |
B. | three-transistor rtl implementation |
C. | multi-transistor rtl implementation |
D. | four-transistor rtl implementation |
Answer» C. multi-transistor rtl implementation |
22. | The primary advantage of RTL technology was that |
A. | it results as low power dissipation |
B. | it uses a minimum number of resistors |
C. | it uses a minimum number of transistors |
D. | it operates swiftly |
Answer» C. it uses a minimum number of transistors |
23. | The disadvantage of RTL is that |
A. | it uses a maximum number of resistors |
B. | it results in high power dissipation |
C. | high noise creation |
D. | it uses minimum number of transistors |
Answer» B. it results in high power dissipation |
24. | TTL circuits with “totem-pole” output stage minimize |
A. | the power dissipation in rtl |
B. | the time consumption in rtl |
C. | the speed of transferring rate in rtl |
D. | propagation delay in rtl |
Answer» A. the power dissipation in rtl |
26. | Diode–transistor logic (DTL) is the direct ancestor of |
A. | register-transistor logic |
B. | transistor–transistor logic |
C. | high threshold logic |
D. | emitter coupled logic |
Answer» B. transistor–transistor logic |
27. | In DTL logic gating function is performed by |
A. | diode |
B. | transistor |
C. | inductor |
D. | capacitor |
Answer» A. diode |
28. | In DTL amplifying function is performed by |
A. | diode |
B. | transistor |
C. | inductor |
D. | capacitor |
Answer» B. transistor |
29. | How many stages a DTL consist of? |
A. | 2 |
B. | 3 |
C. | 4 |
D. | 5 |
Answer» B. 3 |
30. | The full form of CTDL is |
A. | complemented transistor diode logic |
B. | complemented transistor direct logic |
C. | complementary transistor diode logic |
D. | complementary transistor direct logic |
Answer» A. complemented transistor diode logic |
31. | The DTL propagation delay is relatively |
A. | large |
B. | small |
C. | moderate |
D. | negligible |
Answer» A. large |
32. | The way to speed up DTL is to add an across intermediate resister is |
A. | small “speed-up” capacitor |
B. | large “speed-up” capacitor |
C. | small “speed-up” transistor |
D. | large ” speed-up” transistor |
Answer» A. small “speed-up” capacitor |
33. | The process to avoid saturating the switching transistor is performed by |
A. | baker clamp |
B. | james r. biard |
C. | chris brown |
D. | totem-pole |
Answer» A. baker clamp |
34. | A major advantage of DTL over the earlier resistor–transistor logic is the |
A. | increased fan out |
B. | increased fan in |
C. | decreased fan out |
D. | decreased fan in |
Answer» B. increased fan in |
35. | To increase fan-out of the gate in DTL |
A. | an additional capacitor may be used |
B. | an additional resister may be used |
C. | an additional transistor and diode may be used |
D. | only an additional diode may be used |
Answer» C. an additional transistor and diode may be used |
36. | A disadvantage of DTL is |
A. | the input transistor to the resister |
B. | the input resister to the transistor |
C. | the increased fan-in |
D. | the increased fan-out |
Answer» B. the input resister to the transistor |
37. | Compatibility refers to |
A. | the output of a circuit should match with the input of another circuit |
B. | the output of a circuit should match with the input of the same circuit |
C. | the input of a circuit should match with the output of another circuit |
D. | the input of a circuit should match with the output of same circuit |
Answer» A. the output of a circuit should match with the input of another circuit |
38. | The method of connecting a driving device to a loading device is known as |
A. | compatibility |
B. | interface |
C. | sourcing |
D. | sinking |
Answer» B. interface |
39. | The first CML logic was introduced by General Electric in |
A. | 1960 |
B. | 1981 |
C. | 1961 |
D. | 1990 |
Answer» C. 1961 |
40. | Schottky families prevent the saturating using |
A. | transistors |
B. | schottky transistors |
C. | diodes |
D. | schottky diodes |
Answer» D. schottky diodes |
41. | The basic idea of basic CML circuit came from an |
A. | inverter |
B. | buffer |
C. | transistor |
D. | both inverter and buffer |
Answer» D. both inverter and buffer |
42. | The full form of MECL is |
A. | mono emitter coupled logic |
B. | motorola emitter coupled logic |
C. | motorola emitter capacitor logic |
D. | both mono emitter and motorola coupled logic |
Answer» B. motorola emitter coupled logic |
43. | Motorola has offered MECL circuits in logic families. |
A. | 3 |
B. | 4 |
C. | 5 |
D. | 6 |
Answer» C. 5 |
44. | The latest entrant to the ECL family is |
A. | ecl 10k |
B. | ecl 100k |
C. | ecl 1000k |
D. | ecl 10000k |
Answer» B. ecl 100k |
45. | All input of NOR as low produces result as |
A. | low |
B. | mid |
C. | high |
D. | high impedance |
Answer» C. high |
46. | In RTL NOR gate, the output is at logic 1 only when all the inputs are at |
A. | logic 0 |
B. | logic 1 |
C. | +10v |
D. | floating |
Answer» A. logic 0 |
47. | The full form of CMOS is |
A. | capacitive metal oxide semiconductor |
B. | capacitive metallic oxide semiconductor |
C. | complementary metal oxide semiconductor |
D. | complemented metal oxide semiconductor |
Answer» C. complementary metal oxide semiconductor |
48. | The full form of COS-MOS is |
A. | complementary symmetry metal oxide semiconductor |
B. | complementary systematic metal oxide semiconductor |
C. | capacitive symmetry metal oxide semiconductor |
D. | complemented systematic metal oxide semiconductor |
Answer» A. complementary symmetry metal oxide semiconductor |
49. | CMOS is also sometimes referred to as |
A. | capacitive metal oxide semiconductor |
B. | capacitive symmetry metal oxide semiconductor |
C. | complementary symmetry metal oxide semiconductor |
D. | complemented symmetry metal oxide semiconductor |
Answer» C. complementary symmetry metal oxide semiconductor |
51. | Two important characteristics of CMOS devices are |
A. | high noise immunity |
B. | low static power consumption |
C. | high resistivity |
D. | both high noise immunity and low static power consumption |
Answer» D. both high noise immunity and low static power consumption |
52. | CMOS behaves as a/an |
A. | adder |
B. | subtractor |
C. | inverter |
D. | comparator |
Answer» C. inverter |
53. | An important characteristic of a CMOS circuit is the |
A. | noise immunity |
B. | duality |
C. | symmetricity |
D. | noise margin |
Answer» B. duality |
54. | CMOS logic dissipates power than NMOS logic circuits. |
A. | more |
B. | less |
C. | equal |
D. | very high |
Answer» B. less |
55. | Semiconductors are made of |
A. | ge and si |
B. | si and pb |
C. | ge and pb |
D. | pb and au |
Answer» A. ge and si |
56. | Which chip were the first RTC and CMOS RAM chip to be used in early IBM computers, capable of storing a total of 64 bytes? |
A. | the samsung 146818 |
B. | the samsung 146819 |
C. | the motorola 146818 |
D. | the motorola 146819 |
Answer» C. the motorola 146818 |
57. | The full form of ECL is |
A. | emitter-collector logic |
B. | emitter-complementary logic |
C. | emitter-coupled logic |
D. | emitter-cored logic |
Answer» C. emitter-coupled logic |
58. | Which logic is the fastest of all the logic families? |
A. | ttl |
B. | ecl |
C. | htl |
D. | dtl |
Answer» B. ecl |
59. | Sometimes ECL can also be named as |
A. | eel |
B. | cel |
C. | cml |
D. | ccl |
Answer» C. cml |
60. | In an ECL the output is taken from |
A. | emitter |
B. | base |
C. | collector |
D. | junction of emitter and base |
Answer» C. collector |
61. | The ECL behaves as |
A. | not gate |
B. | nor gate |
C. | nand gate |
D. | and gate |
Answer» B. nor gate |
62. | In ECL the fanout capability is |
A. | high |
B. | low |
C. | zero |
D. | sometimes high and sometimes low |
Answer» A. high |
63. | ECL’s major disadvantage is that |
A. | it requires more power |
B. | it’s fanout capability is high |
C. | it creates more noise |
D. | it is slow |
Answer» A. it requires more power |
64. | The full form of SCFL is |
A. | source-collector logic |
B. | source-coupled logic |
C. | source-complementary logic |
D. | source cored logic |
Answer» B. source-coupled logic |
65. | The equivalent of emitter-coupled logic made out of FETs is called |
A. | cml |
B. | scfl |
C. | fecl |
D. | efcl |
Answer» B. scfl |
66. | ECL was invented in by |
A. | 1956, baker clamp |
B. | 1976, james r. biard |
C. | 1956, hannon s. yourke |
D. | 1976, yourke |
Answer» C. 1956, hannon s. yourke |
67. | At the time of invention, an ECL was called as |
A. | source-coupled logic |
B. | current mode logic |
C. | current-steering logic |
D. | emitter-coupled logic |
Answer» C. current-steering logic |
68. | The ECL circuits usually operates with |
A. | negative voltage |
B. | positive voltage |
C. | grounded voltage |
D. | high voltage |
Answer» A. negative voltage |
69. | Low-voltage positive emitter-coupled logic (LVPECL) is a power optimized version of |
A. | ecl |
B. | vecl |
C. | pecl |
D. | lecl |
Answer» C. pecl |
70. | Transistor–transistor logic (TTL) is a class of digital circuits built from |
A. | jfet only |
B. | bipolar junction transistors (bjt) |
C. | resistors |
D. | bipolar junction transistors (bjt) and resistors |
Answer» D. bipolar junction transistors (bjt) and resistors |
71. | TTL was invented in 1961 by |
A. | baker clamp |
B. | james l. buie |
C. | chris brown |
D. | frank wanlass |
Answer» B. james l. buie |
72. | The full form of TCTL is |
A. | transistor-coupled transistor logic |
B. | transistor-capacitor transistor logic |
C. | transistor-complemented transistor logic |
D. | transistor-complementary transistor logic |
Answer» A. transistor-coupled transistor logic |
73. | The ancestor to the first personal computers. |
A. | param 1 |
B. | satyam 1 |
C. | kenbak 1 |
D. | mits altair |
Answer» C. kenbak 1 |
74. | TTL inputs are the emitters of a |
A. | transistor-transistor logic |
B. | multiple-emitter transistor |
C. | resistor-transistor logic |
D. | diode-transistor logic |
Answer» B. multiple-emitter transistor |
76. | Standard TTL circuits operate with a volt power supply. |
A. | 2 |
B. | 4 |
C. | 5 |
D. | 3 |
Answer» C. 5 |
77. | A TTL gate may operate inadvertently as an |
A. | digital amplifier |
B. | analog amplifier |
C. | inverter |
D. | regulator |
Answer» B. analog amplifier |
78. | Which statement below best describes a Karnaugh map? |
A. | it is simply a rearranged truth table |
B. | the karnaugh map eliminates the need for using nand and nor gates |
C. | variable complements can be eliminated by using karnaugh maps |
D. | a karnaugh map can be used to replace boolean rules |
Answer» A. it is simply a rearranged truth table |
79. | Which of the examples below expresses the commutative law of multiplication? |
A. | a + b = b + a |
B. | a • b = b + a |
C. | a • (b • c) = (a • b) • c |
D. | a • b = b • a |
Answer» D. a • b = b • a |
80. | The Boolean expression Y = (AB)’ is logically equivalent to what single gate? |
A. | nand |
B. | nor |
C. | and |
D. | or |
Answer» A. nand |
81. | The systematic reduction of logic circuits is accomplished by: |
A. | symbolic reduction |
B. | ttl logic |
C. | using boolean algebra |
D. | using a truth table |
Answer» C. using boolean algebra |
82. | Each “1” entry in a K-map square represents: |
A. | a high for each input truth table condition that produces a high output |
B. | a high output on the truth table for all low input combinations |
C. | a low output for all possible high input conditions |
D. | a don’t care condition for all possible input truth table combinations |
Answer» A. a high for each input truth table condition that produces a high output |
83. | Each “0” entry in a K-map square represents: |
A. | a high for each input truth table condition that produces a high output |
B. | a high output on the truth table for all low input combinations |
C. | a low output for all possible high input conditions |
D. | a don’t care condition for all possible input truth table combinations |
Answer» A. a high for each input truth table condition that produces a high output |
84. | Looping on a K-map always results in the elimination of |
A. | variables within the loop that appear only in their complemented form |
B. | variables that remain unchanged within the loop |
C. | variables within the loop that appear in both complemented and uncomplemented form |
D. | variables within the loop that appear only in their uncomplemented form |
Answer» C. variables within the loop that appear in both complemented and uncomplemented form |
85. | Which of the following expressions is in the sum-of-products form? |
A. | (a + b)(c + d) |
B. | (a * b)(c * d) |
C. | a* b *(cd) |
D. | a * b + c * d |
Answer» D. a * b + c * d |
86. | What is an ambiguous condition in a NAND based S’-R’ latch? |
A. | s’=0, r’=1 |
B. | s’=1, r’=0 |
C. | s’=1, r’=1 |
D. | s’=0, r’=0 |
Answer» D. s’=0, r’=0 |
87. | In a NAND based S’-R’ latch, if S’=1 & R’=1 then the state of the latch is |
A. | no change |
B. | set |
C. | reset |
D. | forbidden |
Answer» A. no change |
88. | A NAND based S’-R’ latch can be converted into S-R latch by placing |
A. | a d latch at each of its input |
B. | an inverter at each of its input |
C. | it can never be converted |
D. | both a d latch and an inverter at its input |
Answer» D. both a d latch and an inverter at its input |
89. | The difference between a flip-flop & latch is |
A. | both are same |
B. | flip-flop consist of an extra output |
C. | latches has one input but flip-flop has two |
D. | latch has two inputs but flip-flop has one |
Answer» C. latches has one input but flip-flop has two |
90. | How many types of flip-flops are? |
A. | 2 |
B. | 3 |
C. | 4 |
D. | 5 |
Answer» C. 4 |
91. | The S-R flip flop consist of |
A. | 4 and gates |
B. | two additional and gates |
C. | an additional clock input |
D. | 3 and gates |
Answer» B. two additional and gates |
92. | What is one disadvantage of an S-R flip-flop? |
A. | it has no enable input |
B. | it has a race condition |
C. | it has no clock input |
D. | invalid state |
Answer» D. invalid state |
93. | One example of the use of an S-R flip-flop is as |
A. | racer |
B. | stable oscillator |
C. | binary storage register |
D. | transition pulse generator |
Answer» C. binary storage register |
94. | When is a flip-flop said to be transparent? |
A. | when the q output is opposite the input |
B. | when the q output follows the input |
C. | when you can see through the ic packaging |
D. | when the q output is complementary of the input |
Answer» B. when the q output follows the input |
95. | On a positive edge-triggered S-R flip-flop, the outputs reflect the input condition when |
A. | the clock pulse is low |
B. | the clock pulse is high |
C. | the clock pulse transitions from low to high |
D. | the clock pulse transitions from high to low |
Answer» C. the clock pulse transitions from low to high |
96. | What is the hold condition of a flip-flop? |
A. | both s and r inputs activated |
B. | no active s or r input |
C. | only s is active |
D. | only r is active |
Answer» B. no active s or r input |
97. | One example of the use of an S-R flip-flop is as |
A. | transition pulse generator |
B. | racer |
C. | switch debouncer |
D. | astable oscillator |
Answer» C. switch debouncer |
98. | The truth table for an S-R flip-flop has how many VALID entries? |
A. | 1 |
B. | 2 |
C. | 3 |
D. | 4 |
Answer» C. 3 |
99. | When both inputs of a J-K flip-flop cycle, the output will |
A. | be invalid |
B. | change |
C. | not change |
D. | toggle |
Answer» C. not change |
101. | A basic S-R flip-flop can be constructed by cross-coupling of which basic logic gates? |
A. | and or or gates |
B. | xor or xnor gates |
C. | nor or nand gates |
D. | and or nor gates |
Answer» C. nor or nand gates |
102. | The logic circuits whose outputs at any instant of time depends only on the present input but also on the past outputs are called |
A. | combinational circuits |
B. | sequential circuits |
C. | latches |
D. | flip-flops |
Answer» B. sequential circuits |
103. | Whose operations are more faster among the following? |
A. | combinational circuits |
B. | sequential circuits |
C. | latches |
D. | flip-flops |
Answer» A. combinational circuits |
104. | How many types of sequential circuits are? |
A. | 2 |
B. | 3 |
C. | 4 |
D. | 5 |
Answer» A. 2 |
105. | The sequential circuit is also called |
A. | flip-flop |
B. | latch |
C. | strobe |
D. | adder |
Answer» B. latch |
106. | The basic latch consists of |
A. | two inverters |
B. | two comparators |
C. | two amplifiers |
D. | two adders |
Answer» A. two inverters |
107. | In S-R flip-flop, if Q = 0 the output is said to be |
A. | set |
B. | reset |
C. | previous state |
D. | current state |
Answer» B. reset |
108. | The output of latches will remain in set/reset untill |
A. | the trigger pulse is given to change the state |
B. | any pulse given to go into previous state |
C. | they don’t get any pulse more |
D. | the pulse is edge-triggered |
Answer» A. the trigger pulse is given to change the state |
109. | What is a trigger pulse? |
A. | a pulse that starts a cycle of operation |
B. | a pulse that reverses the cycle of operation |
C. | a pulse that prevents a cycle of operation |
D. | a pulse that enhances a cycle of operation |
Answer» A. a pulse that starts a cycle of operation |
110. | A latch is an example of a |
A. | monostable multivibrator |
B. | astable multivibrator |
C. | bistable multivibrator |
D. | 555 timer |
Answer» C. bistable multivibrator |
111. | Latch is a device with |
A. | one stable state |
B. | two stable state |
C. | three stable state |
D. | infinite stable states |
Answer» B. two stable state |
112. | Why latches are called a memory devices? |
A. | it has capability to stare 8 bits of data |
B. | it has internal memory of 4 bit |
C. | it can store one bit of data |
D. | it can store infinite amount of data |
Answer» C. it can store one bit of data |
113. | Two stable states of latches are |
A. | astable & monostable |
B. | low input & high output |
C. | high output & low output |
D. | low output & high input |
Answer» C. high output & low output |
114. | How many types of latches are __ |
A. | 4 |
B. | 3 |
C. | 2 |
D. | 5 |
Answer» A. 4 |
115. | The full form of SR is |
A. | system rated |
B. | set reset |
C. | set ready |
D. | set rated |
Answer» B. set reset |
116. | The SR latch consists of |
A. | 1 input |
B. | 2 inputs |
C. | 3 inputs |
D. | 4 inputs |
Answer» B. 2 inputs |
117. | The outputs of SR latch are |
A. | x and y |
B. | a and b |
C. | s and r |
D. | q and q’ |
Answer» D. q and q’ |
118. | The first step of analysis procedure of SR latch is to |
A. | label inputs |
B. | label outputs |
C. | label states |
D. | label tables |
Answer» B. label outputs |
119. | The inputs of SR latch are |
A. | x and y |
B. | a and b |
C. | s and r |
D. | j and k |
Answer» C. s and r |
120. | When a high is applied to the Set line of an SR latch, then |
A. | q output goes high |
B. | q’ output goes high |
C. | q output goes low |
D. | both q and q’ go high |
Answer» A. q output goes high |
121. | When both inputs of SR latches are low, the latch |
A. | q output goes high |
B. | q’ output goes high |
C. | it remains in its previously set or reset state |
D. | it goes to its next set or reset state |
Answer» C. it remains in its previously set or reset state |
122. | When both inputs of SR latches are high, the latch goes |
A. | unstable |
B. | stable |
C. | metastable |
D. | bistable |
Answer» C. metastable |
123. | The full form of MOS is |
A. | metal oxide semiconductor |
B. | metal oxygen semiconductor |
C. | metallic oxide semiconductor |
D. | metallic oxygen semiconductor |
Answer» A. metal oxide semiconductor |
124. | What are the types of MOSFET devices available? |
A. | p-type enhancement type mosfet |
B. | n-type enhancement type mosfet |
C. | depletion type mosfet |
D. | all of the mentioned |
Answer» D. all of the mentioned |
126. | A technique used to reduce the magnitude of threshold voltage of MOSFET is the |
A. | use of complementary mosfet |
B. | use of silicon nitride |
C. | using thin film technology |
D. | increasing potential of the channel |
Answer» B. use of silicon nitride |
127. | What is used to higher the speed of operation in MOSFET fabrication? |
A. | ceramic gate |
B. | silicon dioxide |
C. | silicon nitride |
D. | poly silicon gate |
Answer» D. poly silicon gate |
128. | Why MOSFET is preferred over BJT in IC components? |
A. | mosfet has low packing density |
B. | mosfet has medium packing density |
C. | mosfet has high packing density |
D. | mosfet has no packing density |
Answer» A. mosfet has low packing density |
129. | Critical defects per unit chip area is for a MOS transistor. |
A. | high |
B. | low |
C. | neutral |
D. | very high |
Answer» B. low |
130. | MOS is being used in |
A. | lsi |
B. | vlsi |
C. | msi |
D. | both lsi and vlsi |
Answer» D. both lsi and vlsi |
131. | The D flip-flop has input. |
A. | 1 |
B. | 2 |
C. | 3 |
D. | 4 |
Answer» A. 1 |
132. | The D flip-flop has output/outputs. |
A. | 2 |
B. | 3 |
C. | 4 |
D. | 1 |
Answer» A. 2 |
133. | A D flip-flop can be constructed from an _ flip-flop. |
A. | s-r |
B. | j-k |
C. | t |
D. | s-k |
Answer» A. s-r |
134. | In D flip-flop, if clock input is HIGH & D=1, then output is |
A. | 0 |
B. | 1 |
C. | forbidden |
D. | toggle |
Answer» A. 0 |
135. | Which of the following is correct for a gated D flip-flop? |
A. | the output toggles if one of the inputs is held high |
B. | only one of the inputs can be high at a time |
C. | the output complement follows the input when enabled |
D. | q output follows the input d when the enable is high |
Answer» D. q output follows the input d when the enable is high |
136. | With regard to a D latch |
A. | the q output follows the d input when en is low |
B. | the q output is opposite the d input when en is low |
C. | the q output follows the d input when en is high |
D. | the q output is high regardless of en’s input state |
Answer» C. the q output follows the d input when en is high |
137. | Which of the following is correct for a D latch? |
A. | the output toggles if one of the inputs is held high |
B. | q output follows the input d when the enable is high |
C. | only one of the inputs can be high at a time |
D. | the output complement follows the input when enabled |
Answer» B. q output follows the input d when the enable is high |
138. | Which of the following describes the operation of a positive edge-triggered D flip-flop? |
A. | if both inputs are high, the output will toggle |
B. | the output will follow the input on the leading edge of the clock |
C. | when both inputs are low, an invalid state exists |
D. | the input is toggled into the flip-flop on the leading edge of the clock and is passed to the output on the trailing edge of the clock |
Answer» B. the output will follow the input on the leading edge of the clock |
139. | A positive edge-triggered D flip-flop will store a 1 when |
A. | the d input is high and the clock transitions from high to low |
B. | the d input is high and the clock transitions from low to high |
C. | the d input is high and the clock is low |
D. | the d input is high and the clock is high |
Answer» B. the d input is high and the clock transitions from low to high |
140. | Why do the D flip-flops receive its designation or nomenclature as ‘Data Flip-flops’? |
A. | due to its capability to receive data from flip-flop |
B. | due to its capability to store data in flip-flop |
C. | due to its capability to transfer the data into flip-flop |
D. | due to erasing the data from the flip-flop |
Answer» C. due to its capability to transfer the data into flip-flop |
141. | The characteristic equation of D-flip-flop implies that |
A. | the next state is dependent on previous state |
B. | the next state is dependent on present state |
C. | the next state is independent of previous state |
D. | the next state is independent of present state |
Answer» D. the next state is independent of present state |
142. | The asynchronous input can be used to set the flip-flop to the |
A. | 1 state |
B. | 0 state |
C. | either 1 or 0 state |
D. | forbidden state |
Answer» C. either 1 or 0 state |
143. | Input clock of RS flip-flop is given to |
A. | input |
B. | pulser |
C. | output |
D. | master slave flip-flop |
Answer» B. pulser |
144. | D flip-flop is a circuit having |
A. | 2 nand gates |
B. | 3 nand gates |
C. | 4 nand gates |
D. | 5 nand gates |
Answer» C. 4 nand gates |
145. | At the end of the clock pulse the value of output Q is uncertain. The situation is referred to as? |
A. | conversion condition |
B. | race around condition |
C. | lock out state |
D. | forbidden state |
Answer» B. race around condition |
146. | Master slave flip flop is also referred to as? |
A. | level triggered flip flop |
B. | pulse triggered flip flop |
C. | edge triggered flip flop |
D. | edge-level triggered flip flop |
Answer» B. pulse triggered flip flop |
147. | In a positive edge triggered JK flip flop, a low J and low K produces? |
A. | high state |
B. | low state |
C. | toggle state |
D. | no change state |
Answer» D. no change state |
148. | If one wants to design a binary counter, the preferred type of flip-flop is |
A. | d type |
B. | s-r type |
C. | latch |
D. | j-k type |
Answer» D. j-k type |
149. | S-R type flip-flop can be converted into D type flip-flop if S is connected to R through |
A. | or gate |
B. | and gate |
C. | inverter |
D. | full adder |
Answer» C. inverter |
151. | Which of the following is the Universal Flip-flop? |
A. | s-r flip-flop |
B. | j-k flip-flop |
C. | master slave flip-flop |
D. | d flip-flop |
Answer» B. j-k flip-flop |
152. | How many types of triggering takes place in a flip flops? |
A. | 3 |
B. | 2 |
C. | 4 |
D. | 5 |
Answer» A. 3 |
153. | The term synchronous means _ |
A. | the output changes state only when any of the input is triggered |
B. | the output changes state only when the clock input is triggered |
C. | the output changes state only when the input is reversed |
D. | the output changes state only when the input follows it |
Answer» B. the output changes state only when the clock input is triggered |
154. | The S-R, J-K and D inputs are called |
A. | asynchronous inputs |
B. | synchronous inputs |
C. | bidirectional inputs |
D. | unidirectional inputs |
Answer» B. synchronous inputs |
155. | The characteristic of J-K flip-flop is similar to |
A. | s-r flip-flop |
B. | d flip-flop |
C. | t flip-flop |
D. | gated t flip-flop |
Answer» A. s-r flip-flop |
156. | A J-K flip-flop can be obtained from the clocked S-R flip-flop by augmenting |
A. | two and gates |
B. | two nand gates |
C. | two not gates |
D. | two or gates |
Answer» A. two and gates |
157. | What is the significance of the J and K terminals on the J-K flip-flop? |
A. | there is no known significance in their designations |
B. | the j represents “jump,” which is how the q output reacts whenever the clock goes high and the j input is also high |
C. | the letters were chosen in honour of jack kilby, the inventory of the integrated circuit |
D. | all of the other letters of the alphabet are already in use |
Answer» C. the letters were chosen in honour of jack kilby, the inventory of the integrated circuit |
158. | 48 MHz. |
A. | 10.24 khz |
B. | 5 khz |
C. | 30.24 khz |
D. | 15 khz |
Answer» B. 5 khz |
159. | How many flip-flops are in the 7475 IC? |
A. | 2 |
B. | 1 |
C. | 4 |
D. | 8 |
Answer» C. 4 |
160. | In parts of the processor, adders are used to calculate |
A. | addresses |
B. | table indices |
C. | increment and decrement operators |
D. | all of the mentioned |
Answer» D. all of the mentioned |
161. | Total number of inputs in a half adder is |
A. | 2 |
B. | 3 |
C. | 4 |
D. | 1 |
Answer» A. 2 |
162. | In which operation carry is obtained? |
A. | subtraction |
B. | addition |
C. | multiplication |
D. | both addition and subtraction |
Answer» B. addition |
163. | If A and B are the inputs of a half adder, the sum is given by |
A. | a and b |
B. | a or b |
C. | a xor b |
D. | a ex-nor b |
Answer» C. a xor b |
164. | If A and B are the inputs of a half adder, the carry is given by |
A. | a and b |
B. | a or b |
C. | a xor b |
D. | a ex-nor b |
Answer» A. a and b |
165. | Half-adders have a major limitation in that they cannot |
A. | accept a carry bit from a present stage |
B. | accept a carry bit from a next stage |
C. | accept a carry bit from a previous stage |
D. | accept a carry bit from the following stages |
Answer» C. accept a carry bit from a previous stage |
166. | The difference between half adder and full adder is |
A. | half adder has two inputs while full adder has four inputs |
B. | half adder has one output while full adder has two outputs |
C. | half adder has two inputs while full adder has three inputs |
D. | all of the mentioned |
Answer» C. half adder has two inputs while full adder has three inputs |
167. | If A, B and C are the inputs of a full adder then the sum is given by |
A. | a and b and c |
B. | a or b and c |
C. | a xor b xor c |
D. | a or b or c |
Answer» C. a xor b xor c |
168. | If A, B and C are the inputs of a full adder then the carry is given by |
A. | a and b or (a or b) and c |
B. | a or b or (a and b) c |
C. | (a and b) or (a and b)c |
D. | a xor b xor (a xor b) and c |
Answer» A. a and b or (a or b) and c |
169. | Half subtractor is used to perform subtraction of |
A. | 2 bits |
B. | 3 bits |
C. | 4 bits |
D. | 5 bits |
Answer» A. 2 bits |
170. | For subtracting 1 from 0, we use to take a from neighbouring bits. |
A. | carry |
B. | borrow |
C. | input |
D. | output |
Answer» B. borrow |
171. | How many outputs are required for the implementation of a subtractor? |
A. | 1 |
B. | 2 |
C. | 3 |
D. | 4 |
Answer» B. 2 |
172. | Let the input of a subtractor is A and B then what the output will be if A = B? |
A. | 0 |
B. | 1 |
C. | a |
D. | b |
Answer» A. 0 |
173. | Let A and B is the input of a subtractor then the output will be |
A. | a xor b |
B. | a and b |
C. | a or b |
D. | a exnor b |
Answer» A. a xor b |
174. | Let A and B is the input of a subtractor then the borrow will be |
A. | a and b’ |
B. | a’ and b |
C. | a or b |
D. | a and b |
Answer» B. a’ and b |
176. | Full subtractor is used to perform subtraction of |
A. | 2 bits |
B. | 3 bits |
C. | 4 bits |
D. | 8 bits |
Answer» B. 3 bits |
177. | The full subtractor can be implemented using |
A. | two xor and an or gates |
B. | two half subtractors and an or gate |
C. | two multiplexers and an and gate |
D. | two comparators and an and gate |
Answer» B. two half subtractors and an or gate |
178. | The output of a subtractor is given by (if A, B and X are the inputs). |
A. | a and b xor x |
B. | a xor b xor x |
C. | a or b nor x |
D. | a nor b xor x |
Answer» B. a xor b xor x |
179. | The output of a full subtractor is same as |
A. | half adder |
B. | full adder |
C. | half subtractor |
D. | decoder |
Answer» B. full adder |
180. | A register is defined as |
A. | the group of latches for storing one bit of information |
B. | the group of latches for storing n-bit of information |
C. | the group of flip-flops suitable for storing one bit of information |
D. | the group of flip-flops suitable for storing binary information |
Answer» D. the group of flip-flops suitable for storing binary information |
181. | The register is a type of |
A. | sequential circuit |
B. | combinational circuit |
C. | cpu |
D. | latches |
Answer» A. sequential circuit |
182. | How many types of registers are? |
A. | 2 |
B. | 3 |
C. | 4 |
D. | 5 |
Answer» C. 4 |
183. | The main difference between a register and a counter is |
A. | a register has no specific sequence of states |
B. | a counter has no specific sequence of states |
C. | a register has capability to store one bit of information but counter has n-bit |
D. | a register counts data |
Answer» A. a register has no specific sequence of states |
184. | In D register, ‘D’ stands for |
A. | delay |
B. | decrement |
C. | data |
D. | decay |
Answer» C. data |
185. | Registers capable of shifting in one direction is |
A. | universal shift register |
B. | unidirectional shift register |
C. | unipolar shift register |
D. | unique shift register |
Answer» B. unidirectional shift register |
186. | A register that is used to store binary information is called |
A. | data register |
B. | binary register |
C. | shift register |
D. | d – register |
Answer» B. binary register |
187. | A shift register is defined as |
A. | the register capable of shifting information to another register |
B. | the register capable of shifting information either to the right or to the left |
C. | the register capable of shifting information to the right only |
D. | the register capable of shifting information to the left only |
Answer» B. the register capable of shifting information either to the right or to the left |
188. | How many methods of shifting of data are available? |
A. | 2 |
B. | 3 |
C. | 4 |
D. | 5 |
Answer» A. 2 |
189. | In serial shifting method, data shifting occurs |
A. | one bit at a time |
B. | simultaneously |
C. | two bit at a time |
D. | four bit at a time |
Answer» A. one bit at a time |
190. | What is a recirculating register? |
A. | serial out connected to serial in |
B. | all q outputs connected together |
C. | a register that can be used over again |
D. | parallel out connected to parallel in |
Answer» A. serial out connected to serial in |
191. | When is it important to use a three-state buffer? |
A. | when two or more outputs are connected to the same input |
B. | when all outputs are normally high |
C. | when all outputs are normally low |
D. | when two or more outputs are connected to two or more inputs |
Answer» A. when two or more outputs are connected to the same input |
192. | After two clock pulses, the register contains |
A. | 10111000 |
B. | 10110111 |
C. | 11110000 |
D. | 11111100 |
Answer» D. 11111100 |
193. | How much storage capacity does each stage in a shift register represent? |
A. | one bit |
B. | two bits |
C. | four bits |
D. | eight bits |
Answer» A. one bit |
194. | The decimal number system represents the decimal number in the form of |
A. | hexadecimal |
B. | binary coded |
C. | octal |
D. | decimal |
Answer» B. binary coded |
195. | 29 input circuit will have total of |
A. | 32 entries |
B. | 128 entries |
C. | 256 entries |
D. | 512 entries |
Answer» D. 512 entries |
196. | BCD adder can be constructed with 3 IC packages each of |
A. | 2 bits |
B. | 3 bits |
C. | 4 bits |
D. | 5 bits |
Answer» C. 4 bits |
197. | The output sum of two decimal digits can be represented in |
A. | gray code |
B. | excess-3 |
C. | bcd |
D. | hexadecimal |
Answer» C. bcd |
198. | The addition of two decimal digits in BCD can be done through |
A. | bcd adder |
B. | full adder |
C. | ripple carry adder |
D. | carry look ahead |
Answer» A. bcd adder |
199. | 3 bits full adder contains |
A. | 3 combinational inputs |
B. | 4 combinational inputs |
C. | 6 combinational inputs |
D. | 8 combinational inputs |
Answer» D. 8 combinational inputs |
201. | Complement of F’ gives back |
A. | f’ |
B. | f |
C. | ff |
D. | ff’ |
Answer» B. f |
202. | Decimal digit in BCD can be represented by |
A. | 1 input line |
B. | 2 input lines |
C. | 3 input lines |
D. | 4 input lines |
Answer» D. 4 input lines |
203. | The number of logic gates and the way of their interconnections can be classified as |
A. | logical network |
B. | system network |
C. | circuit network |
D. | gate network |
Answer» A. logical network |
204. | EPROM uses an array of |
A. | p-channel enhancement type mosfet |
B. | n-channel enhancement type mosfet |
C. | p-channel depletion type mosfet |
D. | n-channel depletion type mosfet |
Answer» B. n-channel enhancement type mosfet |
205. | The EPROM was invented by |
A. | wen tsing chow |
B. | dov frohman |
C. | luis o brian |
D. | j p longwell |
Answer» B. dov frohman |
206. | Address decoding for dynamic memory chip control may also be used for |
A. | chip selection and address location |
B. | read and write control |
C. | controlling refresh circuits |
D. | memory mapping |
Answer» A. chip selection and address location |
207. | Which of the following describes the action of storing a bit of data in a mask ROM? |
A. | a 0 is stored by connecting the gate of a mos cell to the address line |
B. | a 0 is stored in a bipolar cell by shorting the base connection to the address line |
C. | a 1 is stored by connecting the gate of a mos cell to the address line |
D. | a 1 is stored in a bipolar cell by opening the base connection to the address line |
Answer» C. a 1 is stored by connecting the gate of a mos cell to the address line |
208. | The check sum method of testing a ROM |
A. | allows data errors to be pinpointed to a specific memory location |
B. | provides a means for locating and correcting data errors in specific memory locations |
C. | indicates if the data in more than one memory location is incorrect |
D. | simply indicates that the contents of the rom are incorrect |
Answer» D. simply indicates that the contents of the rom are incorrect |
209. | The initial values in all the cells of an EPROM is |
A. | 0 |
B. | 1 |
C. | both 0 and 1 |
D. | alternate 0s and 1s |
Answer» B. 1 |
210. | To store 0 in such a cell, the floating point must be |
A. | reprogrammed |
B. | restarted |
C. | charged |
D. | power off |
Answer» C. charged |
211. | The major disadvantage of RAM is? |
A. | its access speed is too slow |
B. | its matrix size is too big |
C. | it is volatile |
D. | high power consumption |
Answer» C. it is volatile |
212. | Which one of the following is used for the fabrication of MOS EPROM? |
A. | tms 2513 |
B. | tms 2515 |
C. | tms 2516 |
D. | tms 2518 |
Answer» C. tms 2516 |
213. | How many addresses a MOS EPROM have? |
A. | 1024 |
B. | 512 |
C. | 2516 |
D. | 256 |
Answer» C. 2516 |
214. | ROMs retain data when |
A. | power is on |
B. | power is off |
C. | system is down |
D. | all of the mentioned |
Answer» D. all of the mentioned |
215. | When a RAM module passes the checker board test it is |
A. | able to read and write only 0s |
B. | faulty |
C. | probably good |
D. | able to read and write only 1s |
Answer» C. probably good |
216. | What is the difference between static RAM and dynamic RAM? |
A. | static ram must be refreshed, dynamic ram does not |
B. | there is no difference |
C. | dynamic ram must be refreshed, static ram does not |
D. | sram is slower than dram |
Answer» C. dynamic ram must be refreshed, static ram does not |
217. | How many natural states will there be in a 4-bit ripple counter? |
A. | 4 |
B. | 8 |
C. | 16 |
D. | 32 |
Answer» C. 16 |
218. | A ripple counter’s speed is limited by the propagation delay of |
A. | each flip-flop |
B. | all flip-flops and gates |
C. | the flip-flops only with gates |
D. | only circuit gates |
Answer» A. each flip-flop |
219. | One of the major drawbacks to the use of asynchronous counters is that |
A. | low-frequency applications are limited because of internal propagation delays |
B. | high-frequency applications are limited because of internal propagation delays |
C. | asynchronous counters do not have major drawbacks and are suitable for use in high- and low-frequency counting applications |
D. | asynchronous counters do not have propagation delays, which limits their use in high- frequency applications |
Answer» B. high-frequency applications are limited because of internal propagation delays |
220. | Internal propagation delay of asynchronous counter is removed by |
A. | ripple counter |
B. | ring counter |
C. | modulus counter |
D. | synchronous counter |
Answer» D. synchronous counter |
221. | How many flip-flops are required to construct a decade counter? |
A. | 4 |
B. | 8 |
C. | 5 |
D. | 10 |
Answer» A. 4 |
222. | The terminal count of a typical modulus-10 binary counter is |
A. | 0000 |
B. | 1010 |
C. | 1001 |
D. | 1111 |
Answer» C. 1001 |
223. | A ripple counter’s speed is limited by the propagation delay of |
A. | each flip-flop |
B. | all flip-flops and gates |
C. | the flip-flops only with gates |
D. | only circuit gates |
Answer» A. each flip-flop |
224. | A 4-bit counter has a maximum modulus of |
A. | 3 |
B. | 6 |
C. | 8 |
D. | 16 |
Answer» D. 16 |
226. | UP-DOWN counter is also known as |
A. | dual counter |
B. | multi counter |
C. | multimode counter |
D. | two counter |
Answer» C. multimode counter |
227. | In an UP-counter, each flip-flop is triggered by |
A. | the output of the next flip-flop |
B. | the normal output of the preceding flip-flop |
C. | the clock pulse of the previous flip-flop |
D. | the inverted output of the preceding flip-flop |
Answer» B. the normal output of the preceding flip-flop |
228. | In DOWN-counter, each flip-flop is triggered by |
A. | the output of the next flip-flop |
B. | the normal output of the preceding flip-flop |
C. | the clock pulse of the previous flip-flop |
D. | the inverted output of the preceding flip-flop |
Answer» D. the inverted output of the preceding flip-flop |
229. | Binary counter that count incrementally and decrement is called |
A. | up-down counter |
B. | lsi counters |
C. | down counter |
D. | up counter |
Answer» A. up-down counter |
230. | Once an up-/down-counter begins its count sequence, it |
A. | starts counting |
B. | can be reversed |
C. | can’t be reversed |
D. | can be altered |
Answer» D. can be altered |
231. | In 4-bit up-down counter, how many flip-flops are required? |
A. | 2 |
B. | 3 |
C. | 4 |
D. | 5 |
Answer» C. 4 |
232. | A modulus-10 counter must have _ |
A. | 10 flip-flops |
B. | 4 flip-flops |
C. | 2 flip-flops |
D. | synchronous clocking |
Answer» B. 4 flip-flops |
233. | Which is not an example of a truncated modulus? |
A. | 8 |
B. | 9 |
C. | 11 |
D. | 15 |
Answer» A. 8 |
234. | The designation means that the |
A. | up count is active-high, the down count is active-low |
B. | up count is active-low, the down count is active-high |
C. | up and down counts are both active-low |
D. | up and down counts are both active-high |
Answer» A. up count is active-high, the down count is active-low |
235. | The full form of SIPO is |
A. | serial-in parallel-out |
B. | parallel-in serial-out |
C. | serial-in serial-out |
D. | serial-in peripheral-out |
Answer» A. serial-in parallel-out |
236. | How can parallel data be taken out of a shift register simultaneously? |
A. | use the q output of the first ff |
B. | use the q output of the last ff |
C. | tie all of the q outputs together |
D. | use the q output of each ff |
Answer» D. use the q output of each ff |
237. | What is meant by parallel load of a shift register? |
A. | all ffs are preset with data |
B. | each ff is loaded with data, one at a time |
C. | parallel shifting of data |
D. | all ffs are set with data |
Answer» A. all ffs are preset with data |
238. | After three clock pulses, the register contains |
A. | 01110 |
B. | 00001 |
C. | 00101 |
D. | 00110 |
Answer» C. 00101 |
239. | What will be the 4-bit pattern after the second clock pulse? (Right-most bit first) |
A. | 1100 |
B. | 0011 |
C. | 0000 |
D. | 1111 |
Answer» C. 0000 |
240. | In digital logic, a counter is a device which |
A. | counts the number of outputs |
B. | stores the number of times a particular event or process has occurred |
C. | stores the number of times a clock pulse rises and falls |
D. | counts the number of inputs |
Answer» B. stores the number of times a particular event or process has occurred |
241. | A counter circuit is usually constructed of |
A. | a number of latches connected in cascade form |
B. | a number of nand gates connected in cascade form |
C. | a number of flip-flops connected in cascade |
D. | a number of nor gates connected in cascade form |
Answer» C. a number of flip-flops connected in cascade |
242. | How many types of the counter are there? |
A. | 2 |
B. | 3 |
C. | 4 |
D. | 5 |
Answer» B. 3 |
243. | A decimal counter has states. |
A. | 5 |
B. | 10 |
C. | 15 |
D. | 20 |
Answer» B. 10 |
244. | Ripple counters are also called |
A. | ssi counters |
B. | asynchronous counters |
C. | synchronous counters |
D. | vlsi counters |
Answer» B. asynchronous counters |
245. | Synchronous counter is a type of |
A. | ssi counters |
B. | lsi counters |
C. | msi counters |
D. | vlsi counters |
Answer» C. msi counters |
246. | Three decade counter would have |
A. | 2 bcd counters |
B. | 3 bcd counters |
C. | 4 bcd counters |
D. | 5 bcd counters |
Answer» B. 3 bcd counters |
247. | BCD counter is also known as |
A. | parallel counter |
B. | decade counter |
C. | synchronous counter |
D. | vlsi counter |
Answer» B. decade counter |
248. | The parallel outputs of a counter circuit represent the |
A. | parallel data word |
B. | clock frequency |
C. | counter modulus |
D. | clock count |
Answer» D. clock count |
249. | The time from the beginning of a read cycle to the end of tACS/tAA is called as |
A. | write enable time |
B. | data hold |
C. | read cycle time |
D. | access time |
Answer» D. access time |
251. | Which of the following is programmed electrically by the user? |
A. | rom |
B. | eprom |
C. | prom |
D. | eeprom |
Answer» C. prom |
252. | PROMs are available in |
A. | bipolar and mosfet technologies |
B. | mosfet and fet technologies |
C. | fet and bipolar technologies |
D. | mos and bipolar technologies |
Answer» D. mos and bipolar technologies |
253. | Which of the following best describes the fusible-link PROM? |
A. | manufacturer-programmable, reprogrammable |
B. | manufacturer-programmable, one-time programmable |
C. | user-programmable, reprogrammable |
D. | user-programmable, one-time programmable |
Answer» D. user-programmable, one-time programmable |
254. | How can ultraviolet erasable PROMs be recognized? |
A. | there is a small window on the chip |
B. | they will have a small violet dot next to the #1 pin |
C. | their part number always starts with a “u”, such as in u12 |
D. | they are not readily identifiable, since they must always be kept under a small cover |
Answer» A. there is a small window on the chip |
255. | Which part of a Flash memory architecture manages all chip functions? |
A. | program verify code |
B. | floating-gate mosfet |
C. | command code |
D. | input/output pins |
Answer» B. floating-gate mosfet |
256. | How much locations an 8-bit address code can select in memory? |
A. | 8 locations |
B. | 256 locations |
C. | 65,536 locations |
D. | 131,072 locations |
Answer» B. 256 locations |
257. | What is a fusing process? |
A. | it is a process by which data is passed to the memory |
B. | it is a process by which data is read through the memory |
C. | it is a process by which programs are burnout to the diode/transistors |
D. | it is a process by which data is fetched through the memory |
Answer» C. it is a process by which programs are burnout to the diode/transistors |
258. | Fusing process is |
A. | reversible |
B. | irreversible |
C. | synchronous |
D. | asynchronous |
Answer» B. irreversible |
259. | The cell type used inside a PROM is |
A. | link cells |
B. | metal cells |
C. | fuse cells |
D. | electric cells |
Answer» C. fuse cells |
260. | How many types of fuse technologies are used in PROMs? |
A. | 2 |
B. | 3 |
C. | 4 |
D. | 5 |
Answer» B. 3 |
261. | Metal links are made up of |
A. | polycrystalline |
B. | magnesium sulphide |
C. | nichrome |
D. | silicon dioxide |
Answer» C. nichrome |
262. | Silicon links are made up of |
A. | polycrystalline silicon |
B. | polycrystalline magnesium |
C. | nichrome |
D. | silicon dioxide |
Answer» A. polycrystalline silicon |
263. | During programming p-n junction is |
A. | avalanche reverse biased |
B. | avalanche forward biased |
C. | zener reverse biased |
D. | zener reverse biased |
Answer» A. avalanche reverse biased |
264. | The full form of FAMOS is |
A. | floating gate avalanche injection mos |
B. | float gate avalanche injection mos |
C. | floating gate avalanche induction mos |
D. | float gate avalanche induction mos |
Answer» A. floating gate avalanche injection mos |
265. | PROM is programmed by |
A. | eprom programmer |
B. | eeprom programmer |
C. | prom programmer |
D. | rom programmer |
Answer» C. prom programmer |
266. | The PROM starts out with |
A. | 1s |
B. | 0s |
C. | null |
D. | both 1s and 0s |
Answer» B. 0s |
267. | For implementation of PROM, which IC is used? |
A. | ic 74187 |
B. | ic 74186 |
C. | ic 74185 |
D. | ic 74184 |
Answer» B. ic 74186 |
268. | IC 74186 is of |
A. | 1024 bits |
B. | 32 bits |
C. | 512 bits |
D. | 64 bits |
Answer» C. 512 bits |
269. | How many memory locations are addressed using 18 address bits? |
A. | 165,667 |
B. | 245,784 |
C. | 262,144 |
D. | 212,342 |
Answer» C. 262,144 |
270. | How many address bits are needed to operate a 2K * 8-bit memory? |
A. | 10 |
B. | 11 |
C. | 12 |
D. | 13 |
Answer» B. 11 |
271. | What is the bit storage capacity of a ROM with a 1024 × 8 organization? |
A. | 1024 |
B. | 4096 |
C. | 2048 |
D. | 8192 |
Answer» D. 8192 |
272. | The logical sum of two or more logical product terms is called |
A. | sop |
B. | pos |
C. | or operation |
D. | nand operation |
Answer» A. sop |
273. | The expression Y=AB+BC+AC shows the operation. |
A. | ex-or |
B. | sop |
C. | pos |
D. | nor |
Answer» B. sop |
274. | The expression Y=(A+B)(B+C)(C+A) shows the operation. |
A. | and |
B. | pos |
C. | sop |
D. | nand |
Answer» B. pos |
276. | A variable on its own or in its complemented form is known as a |
A. | product term |
B. | literal |
C. | sum term |
D. | word |
Answer» B. literal |
277. | Canonical form is a unique way of representing |
A. | sop |
B. | minterm |
C. | boolean expressions |
D. | pos |
Answer» C. boolean expressions |
278. | There are Minterms for 3 variables (a, b, c). |
A. | 0 |
B. | 2 |
C. | 8 |
D. | 1 |
Answer» C. 8 |
279. | Why is a demultiplexer called a data distributor? |
A. | the input will be distributed to one of the outputs |
B. | one of the inputs will be selected for the output |
C. | the output will be distributed to one of the inputs |
D. | single input gives single output |
Answer» A. the input will be distributed to one of the outputs |
280. | Most demultiplexers facilitate which type of conversion? |
A. | decimal-to-hexadecimal |
B. | single input, multiple outputs |
C. | ac to dc |
D. | odd parity to even parity |
Answer» B. single input, multiple outputs |
281. | In 1-to-4 demultiplexer, how many select lines are required? |
A. | 2 |
B. | 3 |
C. | 4 |
D. | 5 |
Answer» A. 2 |
282. | In a multiplexer the output depends on its |
A. | data inputs |
B. | select inputs |
C. | select outputs |
D. | enable pin |
Answer» B. select inputs |
283. | In 1-to-4 multiplexer, if C1 = 1 & C2 = 1, then the output will be |
A. | y0 |
B. | y1 |
C. | y2 |
D. | y3 |
Answer» D. y3 |
284. | How many select lines are required for a 1-to-8 demultiplexer? |
A. | 2 |
B. | 3 |
C. | 4 |
D. | 5 |
Answer» B. 3 |
285. | How many AND gates are required for a 1-to-8 multiplexer? |
A. | 2 |
B. | 6 |
C. | 8 |
D. | 5 |
Answer» C. 8 |
286. | Which IC is used for the implementation of 1-to-16 DEMUX? |
A. | ic 74154 |
B. | ic 74155 |
C. | ic 74139 |
D. | ic 74138 |
Answer» A. ic 74154 |
287. | The word demultiplex means |
A. | one into many |
B. | many into one |
C. | distributor |
D. | one into many as well as distributor |
Answer» D. one into many as well as distributor |
288. | Why is a demultiplexer called a data distributor? |
A. | the input will be distributed to one of the outputs |
B. | one of the inputs will be selected for the output |
C. | the output will be distributed to one of the inputs |
D. | single input to single output |
Answer» A. the input will be distributed to one of the outputs |
289. | In a multiplexer the output depends on its |
A. | data inputs |
B. | select inputs |
C. | select outputs |
D. | enable pin |
Answer» B. select inputs |
290. | In 1-to-4 multiplexer, if C1 = 0 & C2 = 1, then the output will be |
A. | y0 |
B. | y1 |
C. | y2 |
D. | y3 |
Answer» B. y1 |
291. | In 1-to-4 multiplexer, if C1 = 1 & C2 = 1, then the output will be |
A. | y0 |
B. | y1 |
C. | y2 |
D. | y3 |
Answer» D. y3 |
292. | What is the addition of the binary numbers 11011011010 and 010100101? |
A. | 0111001000 |
B. | 1100110110 |
C. | 11101111111 |
D. | 10011010011 |
Answer» C. 11101111111 |
293. | Perform binary addition: 101101 + 011011 = ? |
A. | 011010 |
B. | 1010100 |
C. | 101110 |
D. | 1001000 |
Answer» D. 1001000 |
294. | Binary subtraction of 100101 – 011110 is |
A. | 000111 |
B. | 111000 |
C. | 010101 |
D. | 101010 |
Answer» A. 000111 |
295. | Perform multiplication of the binary numbers: 01001 × 01011 = ? |
A. | 001100011 |
B. | 110011100 |
C. | 010100110 |
D. | 101010111 |
Answer» A. 001100011 |
296. | 100101 × 0110 = ? |
A. | 1011001111 |
B. | 0100110011 |
C. | 101111110 |
D. | 0110100101 |
Answer» C. 101111110 |
297. | On multiplication of (10.10) and (01.01), we get |
A. | 101.0010 |
B. | 0010.101 |
C. | 011.0010 |
D. | 110.0011 |
Answer» C. 011.0010 |
298. | Divide the binary numbers: 111101 ÷ 1001 and find the remainder |
A. | 0010 |
B. | 1010 |
C. | 1100 |
D. | 0011 |
Answer» D. 0011 |
299. | Divide the binary number (011010000) by (0101) and find the quotient |
A. | 100011 |
B. | 101001 |
C. | 110010 |
D. | 010001 |
Answer» A. 100011 |
301. | Which of the following flip-flop is used by the ring counter? | |
A. | d flip-flops | |
B. | sr flip-flops | |
C. | jk flip-flops | |
D. | t flip-flops | |
Answer» A. d flip-flops | ||
302. | ‘shift_reg’ is used to initialize the |
A. | lsb |
B. | msb |
C. | register type |
D. | register bits |
Answer» B. msb |
303. | How many types of shift operators are there in VHDL? |
A. | three |
B. | four |
C. | five |
D. | six |
Answer» D. six |
304. | How many types of the data type are there in the ring counter? |
A. | one |
B. | two |
C. | three |
D. | more than three |
Answer» D. more than three |
305. | In counter universal clock is not used. |
A. | synchronous counter |
B. | asynchronous counter |
C. | decade counter |
D. | ring counter |
Answer» B. asynchronous counter |
306. | Synchronous counter use global clock, unlike asynchronous counter. |
A. | one |
B. | two |
C. | three |
D. | zero |
Answer» A. one |
307. | How many different states does a decade counter count? |
A. | eight |
B. | nine |
C. | ten |
D. | eleven |
Answer» C. ten |
308. | Output values of Moore type FSM are determined by its |
A. | input values |
B. | output values |
C. | clock input |
D. | current state |
Answer» D. current state |
309. | What happens if the input is high in FSM? |
A. | change of state |
B. | no transition in state |
C. | remains in a single state |
D. | invalid state |
Answer» A. change of state |
310. | What happens if the input is low in FSM? |
A. | change of state |
B. | no transition in state |
C. | remains in a single state |
D. | invalid state |
Answer» B. no transition in state |
311. | . In FSM diagram what does circle represent? |
A. | change of state |
B. | state |
C. | output value |
D. | initial state |
Answer» B. state |
312. | In the FSM diagram, what does arrow between the circles represent? |
A. | change of state |
B. | state |
C. | output value |
D. | initial state |
Answer» A. change of state |
313. | . In the FSM diagram, what does the information below the line in the circle represent? |
A. | change of state |
B. | state |
C. | output value |
D. | initial state |
Answer» C. output value |
314. | Moore machine has states than a mealy machine. |
A. | fewer |
B. | more |
C. | equal |
D. | negligible |
Answer» B. more |
315. | State transition happens in every clock cycle. |
A. | once |
B. | twice |
C. | thrice |
D. | four times |
Answer» A. once |
316. | Output values of mealy type FSM are determined by its |
A. | input values |
B. | output values |
C. | both input values and current state |
D. | current state |
Answer» C. both input values and current state |
317. | What kind of output does mealy machine produce? |
A. | asynchronous |
B. | synchronous |
C. | level |
D. | pulsed |
Answer» A. asynchronous |
318. | States in FSM are represented by |
A. | bits |
B. | bytes |
C. | word |
D. | character |
Answer» A. bits |
319. | What is the first step in writing the VHDL for an FSM? |
A. | to define the vhdl entity |
B. | naming the entity |
C. | defining the data type |
D. | creating the states |
Answer» A. to define the vhdl entity |
320. | Which of the following react faster to inputs? |
A. | sequencer |
B. | generators |
C. | mealy machines |
D. | moore machines |
Answer» C. mealy machines |
321. | What is the first state of FSM? |
A. | wait loop state |
B. | initial state |
C. | output state |
D. | activate pulse state |
Answer» B. initial state |
322. | Mealy machines have states than Moore machine. |
A. | fewer |
B. | more |
C. | equal |
D. | negligible |
Answer» A. fewer |
323. | In mealy type FSM, the path is labelled by which of the following? |
A. | inputs |
B. | outputs |
C. | both inputs and outputs |
D. | current state |
Answer» C. both inputs and outputs |
324. | The process statement used in combinational circuits is called process. |
A. | combinational |
B. | clocked |
C. | unclocked |
D. | sequential |
Answer» A. combinational |
326. | Shift registers comprise of which flip-flops? |
A. | d flip-flops |
B. | sr flip-flops |
C. | jk flip-flops |
D. | t flip-flops |
Answer» A. d flip-flops |
327. | In serial input serial output register, the data of is accessed by the circuit. |
A. | last flip-flop |
B. | first flip-flop |
C. | all flip-flops |
D. | no flip-flop |
Answer» B. first flip-flop |
328. | In PIPO shift register, parallel data can be taken out by |
A. | using the q output of the first flip-flop |
B. | using the q output of the last flip-flop |
C. | using the q output of the second flip-flop |
D. | using the q output of each flip-flop |
Answer» D. using the q output of each flip-flop |
329. | Four bits shift register enables shift control signal in how many clock pulses? |
A. | two clock pulses |
B. | three clock pulses |
C. | four clock pulses |
D. | five clock pulses |
Answer» C. four clock pulses |
330. | Time taken by the shift register to transfer the content is called |
A. | clock duration |
B. | bit duration |
C. | word duration |
D. | duration |
Answer» C. word duration |
331. | Transfer of one bit of information at a time is called |
A. | rotating |
B. | serial transfer |
C. | parallel transfer |
D. | shifting |
Answer» B. serial transfer |
332. | In gated D latch, which of the following is the input symbol? |
A. | d |
B. | q |
C. | en |
D. | clk |
Answer» A. d |
333. | Which of the following is true about packages? |
A. | package is collection of libraries |
B. | library is collection of packages |
C. | package is collection of entities |
D. | entity is collection of packages |
Answer» B. library is collection of packages |
334. | A package may consist of design units. |
A. | 2 |
B. | 3 |
C. | 4 |
D. | 5 |
Answer» A. 2 |
335. | Any item declared in a package declaration section are visible to |
A. | every design unit |
B. | package body only |
C. | library containing that package |
D. | design unit that use the package |
Answer» D. design unit that use the package |
336. | Which of the following is not a in-built package in VHDL? |
A. | std_logic_1164 |
B. | textio |
C. | standard |
D. | std |
Answer» D. std |
337. | Packages increases of the code. |
A. | reusability |
B. | readability |
C. | managing |
D. | resolution |
Answer» A. reusability |
338. | Which of the following can’t have multiple assignments or drivers? |
A. | std_logic |
B. | integer |
C. | std_ulogic |
D. | bit |
Answer» C. std_ulogic |
339. | Which of the following is a not a characteristics of combinational circuits? |
A. | the output of combinational circuit depends on present input |
B. | there is no use of clock signal in combinational circuits |
C. | the output of combinational circuit depends on previous output |
D. | there is no storage element in combinational circuit |
Answer» C. the output of combinational circuit depends on previous output |
340. | Which of the following is not a combinational circuit? |
A. | adder |
B. | code convertor |
C. | multiplexer |
D. | counter |
Answer» D. counter |
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