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Gauss law cannot be expressed in which of the following forms?
Answer: d Explanation: Gauss law can be expressed in differential or point form as, Div (D)= ρv and in integral form as ∫∫ D.ds = Q = ψ . It is not possible to express it using Stoke’s theorem.
Answer: d
Explanation: Gauss law can be expressed in differential or point form as,
Div (D)= ρv and in integral form as ∫∫ D.ds = Q = ψ . It is not possible to express it using
Stoke’s theorem.
See lessWith Gauss law as reference which of the following law can be derived?
Answer: c Explanation: From Gauss law, we can compute the electric flux density. This in turn can be used to find electric field intensity. We know that F = qE. Hence force can be computed. This gives the Coulomb’s law.
Answer: c
Explanation: From Gauss law, we can compute the electric flux density. This in turn can
be used to find electric field intensity. We know that F = qE. Hence force can be
computed. This gives the Coulomb’s law.
See lessThe potential of a coaxial cylinder with charge density 1 unit , inner radius 1m and outer cylinder 2m is (in 109 )
Answer: c Explanation: The potential of a coaxial cylinder will be ρl ln(b/a)/2πε, where ρl = 1, b = 2m and a = 1m. We get V = 12.47 X 109 volts.
Answer: c
Explanation: The potential of a coaxial cylinder will be ρl ln(b/a)/2πε, where ρl = 1, b =
2m and a = 1m. We get V = 12.47 X 109 volts.
See lessFind the potential due to a charged ring of density 2 units with radius 2m and the point at which potential is measured is at a distance of 1m from the ring.
Answer: d Explanation: The potential due to a charged ring is given by λa/2εr, where a = 2m and r = 1m. We get V = 72π volts.
Answer: d
Explanation: The potential due to a charged ring is given by λa/2εr, where a = 2m and r
= 1m. We get V = 72π volts.
See lessGauss law cannot be used to find which of the following quantity?
Answer: d Explanation: Permittivity is constant for a particular material(say permittivity of water is 1). It cannot be determined from Gauss law, whereas the remaining options can be computed from Gauss law.
Answer: d
Explanation: Permittivity is constant for a particular material(say permittivity of water is
1). It cannot be determined from Gauss law, whereas the remaining options can be
computed from Gauss law.
See lessGauss law for magnetic fields is given by
Answer: b Explanation: The divergence of magnetic flux density is always zero. This is called Gauss law for magnetic fields. It implies the non-existence of magnetic monopoles in any magnetic field.
Answer: b
Explanation: The divergence of magnetic flux density is always zero. This is called
Gauss law for magnetic fields. It implies the non-existence of magnetic monopoles in
any magnetic field.
See lessThree charged cylindrical sheets are present in three spaces with σ = 5 at R = 2m, σ = -2 at R = 4m and σ = -3 at R = 5m. Find the flux density at R = 1m.
Answer: a Explanation: Since 1m does not enclose any cylinder (three Gaussian surfaces of radius 2m, 4m, 5m exists), the charge density and charge becomes zero according to Gauss law. Thus flux density is also zero.
Answer: a
Explanation: Since 1m does not enclose any cylinder (three Gaussian surfaces of
radius 2m, 4m, 5m exists), the charge density and charge becomes zero according
to Gauss law. Thus flux density is also zero.
See lessGiven E = 40xyi + 20×2 j + 2k. Calculate the potential between two points (1,-1,0) and (2,1,3).
Answer: b Explanation: V = -∫ E.dl = -∫ (40xy dx + 20x2 dy + 2 dz), from (2,1,3) to (1,-1,0), we get Vpq on integrating from Q to P. Vpq = 106 volts.
Answer: b
Explanation: V = -∫ E.dl = -∫ (40xy dx + 20×2 dy + 2 dz), from (2,1,3) to (1,-1,0), we get
Vpq on integrating from Q to P. Vpq = 106 volts.
See lessThe potential difference in an open circuit is
Answer: c Explanation: In an open circuit no current exists due to non-existence of loops. Also voltage/potential will be infinity in an open circuit
Answer: c
Explanation: In an open circuit no current exists due to non-existence of loops. Also
voltage/potential will be infinity in an open circuit
See lessThe potential taken between two points across a resistor will be
Answer: b Explanation: The resistor will absorb power and dissipate it in the form of heat energy. The potential between two points across a resistor will be negative.
Answer: b
Explanation: The resistor will absorb power and dissipate it in the form of heat energy.
The potential between two points across a resistor will be negative.
See less