Poll Results
No votes. Be the first one to vote.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
To calculate the energy in an electric field using the given electric flux density and the electric field intensity, one generally needs a formula that relates these quantities to energy. However, the electric flux density (usually denoted as (mathbf{D})) and electric field intensity (usually denoted as (mathbf{E})) are typically used to describe the field properties rather than directly calculating energy stored in the field. The energy density ((u)) in an electric field can be calculated using various formulas depending on the context and units, but a common formula in the context of electromagnetism, using SI units, is given by:
[ u = frac{1}{2} epsilon E^2 ]
Where:
– (u) is the energy density (energy per unit volume, in joules per cubic meter),
– (epsilon) is the permittivity of the medium (in farads per meter; for vacuum, (epsilon_0 = 8.85 times 10^{-12} , text{F/m})),
– (E) is the electric field intensity (in volts per meter).
Given just the flux density ((mathbf{D})) and the electric field intensity ((E)) without specifying units or the medium’s permittivity, there’s not a standard calculation that directly uses both “units” of flux density and “units” of field intensity to give energy in a generally accepted physical
Answer: a
Explanation: The energy in an electric field is given by, W = 0.5 x D x E, where D = 6
and E = 4. We get W = 0.5 x 6 x 4 = 12 units.