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To compute Gauss’s law for a given electric displacement field ( mathbf{D} ) and to find the charge enclosed using a volume integral, we work step by step through the problem. Gauss’s law in differential form relates the divergence of the electric displacement field ( mathbf{D} ) to the free charge density ( rho_{free} ) present in the medium:
[
nabla cdot mathbf{D} = rho_{free}
]
Given:
[
mathbf{D} = frac{10rho^3}{4} hat{mathbf{i}}
]
This is given in cylindrical coordinates ((rho, phi, z)) but with a slight confusion in the notation since (hat{mathbf{i}}) is typically used for Cartesian coordinates. Assuming it’s meant to represent the radial component in cylindrical coordinates, it should correctly be (hat{rho}) instead of (hat{mathbf{i}}), so:
[
mathbf{D} = frac{10rho^3}{4} hat{rho}
]
To compute the charge enclosed within a cylindrical volume defined by ( rho = 4m ), between ( z = 0 ) and ( z = 5 ), we first compute the volume integral of the charge density ( rho_{free} ).
Since ( nabla
d
Explanation: Q = D.ds = ∫∫∫ Div (D) dv, where RHS needs to be computed.
The divergence of D given is, Div(D) = 10 ρ2 and dv = ρ dρ dφ dz. On integrating, ρ = 0-
>4, φ = 0->2π and z = 0->5, we get Q = 6400 π.