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To compute Gauss’s Law using the displacement field D, we first write down Gauss’s Law for electric displacement fields:
[
Phi_D = oint_S mathbf{D} cdot dmathbf{A} = Q_{free}
]
Where Q_free is the free charge enclosed by the surface S. Here, the displacement field is given as:
[
mathbf{D} = frac{10rho^3}{4} mathbf{i}
]
In cylindrical coordinates, D can be expressed as a function of ρ, and given constants indicate that D has only an i component (along the x-axis).
Given:
– ρ = 4 m
– z = 0 (which we could consider as the bottom face of a cylindrical volume)
– z = 5 (top face of the volume)
1. Calculate D at ρ = 4 m:
[
mathbf{D} = frac{10(4)^3}{4} mathbf{i} = frac{10 times 64}{4} mathbf{i} = 160 mathbf{i}
]
2. Define the Gaussian surface: A cylinder with radius 4 m and height 5 m.
3. Calculate the area vector: The enclosed area of the Gaussian surface includes the curved surface and two flat circular areas.
– Curved surface area
Answer: d
Explanation: ∫∫ D.ds = ∫∫ (10ρ3/4).(ρ dφ dz), which is the integral to be evaluated. Put ρ =4m, z = 0→5 and φ = 0→2π, the integral evaluates to 6400π