Find the area of a right angled triangle with sides of 90 degree unit and the functions described by L = cos y and M = sin x.

The question seems to involve a misunderstanding or is improperly formed for a couple of reasons:

1. When you refer to a right-angled triangle with “sides of 90 degree unit,” it suggests a confusion. In geometry, the sides of a triangle are measured in units of length (not degrees, which measure angles). A right-angled triangle is defined by having one angle measuring 90 degrees, but the lengths of the sides are not described in degrees.

2. The functions L = cos y and M = sin x appear to introduce variables y and x as angles, but without specific values or a clear connection to the triangle’s sides, they cannot directly contribute to finding the area of the triangle. Normally, to find the area of a right-angled triangle, you need the lengths of two sides that meet at the right angle (often referred to as the base and the height), and then you use the formula:

[ text{Area} = frac{1}{2} times text{base} times text{height} ]

Without specifying the lengths of the triangle’s sides or how the functions L and M relate to those lengths (for instance, if they represent the triangle’s angles or if they somehow define the lengths of sides in relation to an angle), it’s not possible to provide an answer that integrates all given information directly.

If there’s a specific right-angled triangle scenario with known side lengths or specific angles (apart from