jangyasinniTeacher
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To find the mean free path of an electron traveling at a speed of (18 , text{m/s}) in (2 , text{seconds}), we need to understand what mean free path is first. The mean free path is the average distance traveled by a moving particle (such as an electron) between successive impacts (collisions), which modify its direction or energy or other particle properties. However, to calculate the mean free path directly from the information provided (speed and time) without details about the frequency or probability of collisions, or the specifics of the medium the electron is moving through (like its density or the cross-sectional area for collision), is not straightforward.
Given the velocity of the electron ((v = 18 , text{m/s})) and the time ((t = 2 , text{s})), you might be looking for the distance traveled rather than the mean free path per se, as the actual calculation of mean free path requires statistical mechanics and knowledge of the conditions (like pressure and temperature for gases or the material properties for solids or liquids).
However, if we interpret your question as seeking the distance traveled under the assumption that this distance is a proxy for the “mean free path” in a very idealized context where every 2 seconds the electron’s path is somehow altered, here’s a simple calculation:
Distance traveled, (d = vt), where (v = 18 , text{m
b
Explanation: The mean free path is defined as the average distance travelled by an
electron before collision takes place. It is given by, d = v x τc, where v is the velocity and
τc is the collision time. Thus d = 18 x 2 = 36m.
b) 36
Explanation: The mean free path is defined as the average distance travelled by an
electron before collision takes place. It is given by, d = v x τc, where v is the velocity and τc is the collision time. Thus d = 18 x 2 = 36m.