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Home/ Questions/Q 1034257
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jangyasinni
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jangyasinniTeacher
Asked: August 28, 20242024-08-28T23:16:30+05:30 2024-08-28T23:16:30+05:30In: Education

Find the permittivity of the surface when a wave incident at an angle 60 is reflected by the surface at 45 in air.

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0%a) 1.41 ( 0 voters )
0%b) 3.5 ( 0 voters )
0%c) 2.2 ( 0 voters )
100%d) 1.73 ( 1 voter )
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    1. Quearn
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      Quearn Quearnist
      2024-08-28T23:16:46+05:30Added an answer on August 28, 2024 at 11:16 pm

      The permittivity of a surface or medium is a material property that describes how an electric field affects, and is affected by, the medium. It’s a fundamental property related to electric polarizability of the medium and affects how electromagnetic waves propagate through it. The scenario described—a wave incident at 60 degrees being reflected at 45 degrees in air—does not directly provide enough information to calculate permittivity as traditionally defined.

      Permittivity is typically denoted by the symbol (epsilon), and the permittivity of free space ((epsilon_0)) is a constant, approximately equal to (8.85 times 10^{-12} F/m) (farads per meter). The relative permittivity ((epsilon_r)) of a material is the ratio of its permittivity to the permittivity of free space. This property does not depend on the angle of incidence or reflection of waves but on the material properties themselves.

      The information provided seems to relate more to the law of reflection or Snell’s Law, which deals with the angles of incidence and reflection/transmission and the indices of refraction for the materials at the interface. Proper application of Snell’s Law requires knowing the indices of refraction of the involved mediums. These are related to the permittivity (as well as the permeability) of those mediums, but the reflection angles alone, without additional context about the materials involved or the wave’s nature (such as whether it is

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    2. jangyasinni
      jangyasinni Teacher
      2024-08-28T23:16:58+05:30Added an answer on August 28, 2024 at 11:16 pm

      d

      Explanation: From the relations of the boundary conditions of a dielectric-dielectric

      interface, we get tan θ1/tan θ2 = ε1/ε2. Thus tan 60/tan 45 = ε1/1. We get ε1 = tan 60 =

      1.73

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    3. prasanjit
      prasanjit Teacher
      2024-09-06T13:07:00+05:30Added an answer on September 6, 2024 at 1:07 pm

      d
      Explanation: From the relations of the boundary conditions of a dielectric-dielectric
      interface, we get tan θ1/tan θ2 = ε1/ε2. Thus tan 60/tan 45 = ε1/1. We get ε1 = tan 60 =1.73.

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