Find the resistance of a cylinder of area 200 units and length 100m with conductivity of 12 units.

To find the resistance (R) of a cylinder, we can use the formula derived from Ohm’s Law, which relates the resistivity ( rho ) (inverse of conductivity ( sigma )), the length (L) of the material, and the cross-sectional area (A):

[ R = frac{rho L}{A} ]

However, we have the conductivity ( sigma ) given, so we can modify the formula to use conductivity directly:

[ R = frac{L}{sigma A} ]

Given the values:

– (L = 100 , text{m} )

– (A = 200 , text{units}^2 ) (Note: The unit of area should typically be in square meters for the calculation to be in standard SI units, but I’ll proceed with the units given.)

– ( sigma = 12 , text{units} ) (Again, conductivity’s SI unit is Siemens per meter, S/m, but I’ll proceed with the units provided.)

We plug these into the modified formula:

[ R = frac{100}{12 times 200} ]

[ R = frac{100}{2400} ]

[ R = frac{1}{24} , text{units} ]

Thus, the resistance (R) of the cylinder is ( frac{1}{24} ) of the units specified