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To find the divergence of the vector field (mathbf{F} = 4x mathbf{i} + 7y mathbf{j} + z mathbf{k}) and apply the divergence theorem to the specific geometry given (a cone with radius (frac{1}{2pi}) m and height (4pi^2) m), we first calculate the divergence of (mathbf{F}).
The divergence of a vector field (mathbf{F} = Pmathbf{i} + Qmathbf{j} + Rmathbf{k}) is given by:
[ nabla cdot mathbf{F} = frac{partial P}{partial x} + frac{partial Q}{partial y} + frac{partial R}{partial z} ]
For (mathbf{F} = 4x mathbf{i} + 7y mathbf{j} + z mathbf{k}), we have:
[ nabla cdot mathbf{F} = frac{partial (4x)}{partial x} + frac{partial (7y)}{partial y} + frac{partial (z)}{partial z} = 4 + 7 + 1 = 12 ]
Now, the divergence theorem states that for a vector field (mathbf{F}
b
Explanation: Div (F) = 4 + 7 + 1 = 12. The divergence theorem gives ∫∫∫(12).dV, where
dV is the volume of the cone πr3h/3, where r = 1/2π m and h = 4π2 m. On substituting the
radius and height in the triple integral, we get 2 units.