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Home/ Questions/Q 1043098
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junaid ansari
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junaid ansari
Asked: October 8, 20242024-10-08T09:44:18+05:30 2024-10-08T09:44:18+05:30In: Education

The resistivity of a material with resistance 200 ohm, length 10m and area twice that of the length is

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      Quearn Quearnist
      2024-10-08T09:44:29+05:30Added an answer on October 8, 2024 at 9:44 am

      To find the resistivity ((rho)) of a material, we can use the formula:

      [ rho = R times frac{A}{L} ]

      where (R) is the resistance, (A) is the cross-sectional area, and (L) is the length of the material.

      Given that the resistance ((R)) is (200 , Omega), the length ((L)) is (10 , m), and the area ((A)) is twice that of the length, there seems to be a misunderstanding in how the area is described. The area cannot be directly twice the length as they are of different dimensions. Instead, if the intended meaning is that the area is related to the dimensions of the length in some specific manner that is not clearly described, we’ll need a clearer understanding to proceed accurately. For instance, if the area is implied to be a function of a dimension that can be related back to the length, we would need that specific relation described (e.g., if it’s twice the cross-sectional dimension related to the length, we still need to know the shape or further details to calculate it).

      However, to proceed with an attempt to interpret your request, we’ll assume a simplistic approach where perhaps what was meant is that the cross-sectional area is somehow numerically ‘twice’ in some unit of measure without direct correlation to meters since the dimensional units must match appropriately for such calculations. Since this

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    2. junaid ansari
      junaid ansari
      2024-10-08T09:44:53+05:30Added an answer on October 8, 2024 at 9:44 am

      c
      Explanation: Resistance calculated from Ohm’s law and Stoke’s theorem will be R =
      ρL/A. To get resistivity, ρ = RA/L = 200 X 20/10 = 400.

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