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The subnet ID of a host with an IP address 172.16.66.0/21 can be determined by applying the subnet mask (/21) to the IP address. A /21 subnet mask means the first 21 bits are the network portion of the address, with the remaining bits designated for host addresses within that network.
To calculate the subnet ID, convert the IP address and the subnet mask into binary, then perform a logical AND operation between the two.
IP address: 172.16.66.0 in binary is 10101100.00010000.01000010.00000000
Subnet mask: /21 means the first 21 bits are ‘1’, and the rest are ‘0’. In binary, this is 11111111.11111111.11111000.00000000 which translates back into dotted-decimal notation as 255.255.248.0
Performing the AND operation:
– 10101100.00010000.01000010.00000000 (IP address in binary)
– 11111111.11111111.11111000.00000000 (/21 subnet mask in binary)
= 10101100.00010000.01000000.00000000
Converting the result back to decimal gives us the subnet ID: 172.16.64.0
Therefore, the subnet ID for a host with an IP address 172.16.66.0
C. 172.16.64.0