A single phase full bridge inverter circuit, has load R = 2 Ω and dc source Vs = 230 V. Find the value of power delivered to the load in watts only due to the fundamental component of the load current

To find the power delivered to the load in watts due to the fundamental component of the load current in a single-phase full-bridge inverter circuit, we can use the formula for power:

[

P = I_{rms}^2 times R

]

However, we first need to determine the root mean square (rms) value of the fundamental component of the current. For a full-bridge inverter with a resistive load, the rms current can be derived from the dc source voltage (( V_s )) and the load resistance (( R )).

For a full-bridge inverter, the output fundamental voltage ( V_{1} ) is given by:

[

V_{1} = frac{V_s}{pi}

]

Substituting ( V_s = 230 , V ):

[

V_{1} = frac{230}{pi} approx 73.24 , V

]

Now, we can find the fundamental component of the current:

[

I_{1} = frac{V_{1}}{R} = frac{73.24}{2} approx 36.62 , A

]

The rms current ( I_{rms} ) is currently the same as the effective current flowing through the resistive load since it primarily consists of the fundamental component in a purely resistive load. To find power:

[

P = I_{r