For the circuit shown in the figure below, V9 is the AC voltage source with peak value Vm. The waveform of the load voltage at the resistor has a a) peak value of (Vm+V1) in the negative half cycle b) peak value of (Vm-V1) in the positive half cycle c) peak value of (Vm+V1) in the positive half cycle d) peak value of (Vm-V1) in the negative half cycle
For the circuit shown in the figure below, V9 is the AC voltage source with peak value Vm. The waveform of the load voltage at the resistor has a a) peak value of (Vm+V1) in the negative half cycle b) peak value of (Vm-V1) in the positive half cycle c) peak value of (Vm+V1) in the positive half cycle d) peak value of (Vm-V1) in the negative half cycle
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Explanation: Diode is reversed biased in the negative half cycle. In the positive half
cycle, apply KVL to get the value of peak voltage at the load. Peak value = Vm + V1, as
V1 is aiding the positive anode of the diode.