Six equal point charges Q = 10nC are located at 2,3,4,5,6,7m. Find the potential at origin.

To find the electric potential at the origin due to six point charges, (Q = 10 , text{nC} = 10 times 10^{-9} , text{C}), located at distances of 2, 3, 4, 5, 6, and 7m, we can use the formula:

[V = frac{1}{4piepsilon_0} sum frac{Q}{r_i}]

Where:

– (V) is the electric potential,

– (Q) is the charge,

– (r_i) is the distance of each charge from the point where the potential is being calculated (in this case, the origin),

– (epsilon_0) is the permittivity of free space ((8.85 times 10^{-12} , text{F/m})).

Plugging in the values:

[V = frac{1}{4pi(8.85 times 10^{-12})} left( frac{10 times 10^{-9}}{2} + frac{10 times 10^{-9}}{3} + frac{10 times 10^{-9}}{4} + frac{10 times 10^{-9}}{5} + frac{10 times 10^{-9}}{6} + frac{10 times 10