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Answer: c
Explanation: The potential due a dipole at a point P will be V = m cos θ/(4πεr2).
Now it is given that potential on the midpoint, which means P is on midpoint, then the distance from midpoint and P will be zero. When r = 0 is put in the above equation, we get V = ∞. This shows that the potential of a dipole at its midpoint will be maximum/infinity.
In the case of an electric dipole, the potential at the midpoint of the two charges of equal magnitude but opposite in sign is zero. This occurs because the electric potential due to a point charge is given by (V = kfrac{q}{r}), where (k) is Coulomb’s constant, (q) is the charge, and (r) is the distance from the charge to the point at which the potential is being calculated.
For a dipole consisting of charges (+q) and (-q) separated by a distance (2a), the midpoint is equidistant from both charges, say at a distance (a). Thus, the potential at the midpoint due to the positive charge (+q) is (V_+ = kfrac{q}{a}), and the potential due to the negative charge (-q) is (V_- = kfrac{-q}{a}). Since these potentials have equal magnitudes but opposite signs, they add up to zero:
[V_{text{midpoint}} = V_+ + V_- = kfrac{q}{a} + kfrac{-q}{a} = 0]
Therefore, the potential due to the dipole on the midpoint of the two charges will be 0.