A single phase full bridge inverter is fed from a dc source such that the fundamental component of output voltage = 230 V. Find the rms value of SCR and diode current respectively, for a R load of 2 Ω

To determine the RMS value of SCR (Silicon Controlled Rectifier) and diode current for a single-phase full bridge inverter that feeds a resistive load, we can follow these steps:

1. Output Voltage (Fundamental Component): Given that the fundamental component of output voltage (V_out) is 230 V.

2. RMS Output Voltage: In a full bridge inverter, the RMS value of the output voltage can be found using the relation:

[

V_{rms} = frac{V_{out}}{sqrt{2}}

]

So,

[

V_{rms} = frac{230 V}{sqrt{2}} approx 162.63 V

]

3. Load Resistance (R load): Given as ( R = 2 , Omega ).

4. Current Through Load: The current (I_load) through the load can be calculated using Ohm’s Law:

[

I_{load} = frac{V_{rms}}{R}

]

Substituting the values,

[

I_{load} = frac{162.63 V}{2 , Omega} approx 81.31 A

]

5. RMS Value of SCR and Diode Current: In a single-phase full bridge inverter, the SCR and diode conduct alternately. Each SCR conducts for half the