Compute the conductivity when the current density is 12 units and the electric field is 20 units. Also identify the nature of the material.

To compute the conductivity ((sigma)), we use the relation given by Ohm’s law at the microscopic level, which is:

[

sigma = frac{J}{E}

]

where:

– (sigma) is the conductivity,

– (J) is the current density, and

– (E) is the electric field.

Given that the current density (J = 12) units and the electric field (E = 20) units, we substitute these values into the formula:

[

sigma = frac{12}{20} = 0.6

]

Thus, the conductivity of the material is (0.6) units.

Regarding the nature of the material, conductivity values give us insight into whether a material is a good conductor, semiconductor, or insulator:

– Conductors have high conductivity (e.g., metals).

– Semiconductors have intermediate conductivity, which can vary with doping, temperature, and other factors.

– Insulators have very low conductivity.

Since the conductivity is (0.6) units without a specific reference scale or comparison to known materials’ conductivities, it’s difficult to definitively categorize the material as a conductor, semiconductor, or insulator. However, here are general pointers:

– If this value is compared to known conductors (like copper, for which conductivity is in the order of (10^7) S/m under standard conditions), (0.6) units might suggest it