Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
For an infinite transmission line, the characteristic impedance is given by 50 ohm. Find the input impedance.
d Explanation: From the transmission line equation, the infinite line will have an input impedance same as that of the characteristic impedance. Thus Zin = Zo for l->∞. This shows that the line will be matched. The input impedance for the given case is 50 ohm.
d
See lessExplanation: From the transmission line equation, the infinite line will have an input
impedance same as that of the characteristic impedance. Thus Zin = Zo for l->∞. This
shows that the line will be matched. The input impedance for the given case is 50 ohm.
Identify the secondary parameter from the options given below.
c Explanation: Primary parameters are directly observed from the circuit characteristics. Secondary parameters are derived or calculated from the primary parameters. R, L, C, G are primary parameters, whereas α, β, γ, Zo are secondary parameters.
c
See lessExplanation: Primary parameters are directly observed from the circuit characteristics. Secondary parameters are derived or calculated from the primary parameters. R, L, C, G are primary parameters, whereas α, β, γ, Zo are secondary parameters.
The velocity of wave in the air medium is
c Explanation: The light is travelling at its fastest speed in air medium. Thus the velocity of a wave in the air medium is assumed to have the speed of light. It is given by c = 3 x 108.
c
See lessExplanation: The light is travelling at its fastest speed in air medium. Thus the velocity of a wave in the air medium is assumed to have the speed of light. It is given by c = 3 x 108.
The propagation constant of a wave with attenuation and phase constant given by 2 and 3 respectively is
c Explanation: The propagation constant is given by γ = α + jβ. Given that α = 2 and β = 3. Thus we get the propagation constant as γ = 2 + 3j.
c
See lessExplanation: The propagation constant is given by γ = α + jβ. Given that α = 2 and β = 3. Thus we get the propagation constant as γ = 2 + 3j.
The unit of attenuation constant is
c Explanation: Attenuation constant is the measure of the power loss of the wave during its transmission. It is expressed in terms of neper and 1 neper= 8.686 decibel/m.
c
See lessExplanation: Attenuation constant is the measure of the power loss of the wave during
its transmission. It is expressed in terms of neper and 1 neper= 8.686 decibel/m.
The electrical length in a transmission line refers to the
a Explanation: The electrical length in a transmission line refers to the product of the attenuation constant α and the length of the line l. It is given by αl.
a
See lessExplanation: The electrical length in a transmission line refers to the product of the
attenuation constant α and the length of the line l. It is given by αl.
The frequency of a wave travelling in a transmission line with velocity 4 x 108 and wavelength 3 units is
b Explanation: The frequency and wavelength relation is given by f = v/λ. On substituting for v and λ, we get f = 4 x 108 /3 = 0.133 GHz.
b
See lessExplanation: The frequency and wavelength relation is given by f = v/λ. On substituting for v and λ, we get f = 4 x 108 /3 = 0.133 GHz.
The phase constant of a wave with a wavelength of 2 units is given by
b Explanation: The phase constant is given by β = 2π/λ. On substituting for λ = 2, we get β= 2π/2 = 3.14 units.
b
See lessExplanation: The phase constant is given by β = 2π/λ. On substituting for λ = 2, we get β= 2π/2 = 3.14 units.
The wavelength of a wave with a frequency of 6 GHz in air is
d Explanation: The wavelength is given by the ratio of the velocity to the frequency of the wave. In air medium, the velocity can be assumed as the speed of light. On substituting for v and f, we get λ = v/f = 3×108/6×109 = 0.05 units.
d
See lessExplanation: The wavelength is given by the ratio of the velocity to the frequency of the wave. In air medium, the velocity can be assumed as the speed of light. On substituting for v and f, we get λ = v/f = 3×108/6×109 = 0.05 units.
The wavelength of a line with a phase constant of 6.28 units is
b Explanation: The wavelength and the phase constant are related by λ = 2π/β, where β is given as 6.28. On substituting for β, we get λ = 2π/6.28 = 1 unit.
b
See lessExplanation: The wavelength and the phase constant are related by λ = 2π/β, where β is given as 6.28. On substituting for β, we get λ = 2π/6.28 = 1 unit.