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Calculate the phase constant of a wave with skin depth of 2.5 units.
d Explanation: The skin depth is the reciprocal of the phase constant and the attenuation constant too. Thus δ = 1/β. On substituting for δ = 2.5, we get β = 1/δ = 1/2.5 = 2/5 units.
d
See lessExplanation: The skin depth is the reciprocal of the phase constant and the attenuation constant too. Thus δ = 1/β. On substituting for δ = 2.5, we get β = 1/δ = 1/2.5 = 2/5 units.
Calculate the skin depth of a material with attenuation constant of 2 units.
c Explanation: The skin depth of a material is the reciprocal of the attenuation constant. Thus δ = 1/α. On substituting for α = 2, we get δ = ½ = 0.5 units.
c
See lessExplanation: The skin depth of a material is the reciprocal of the attenuation constant.
Thus δ = 1/α. On substituting for α = 2, we get δ = ½ = 0.5 units.
The intrinsic impedance is the ratio of square root of
b Explanation: The intrinsic impedance is the impedance of a particular material. It is the ratio of square root of the permeability to permittivity. For air, the intrinsic impedance is 377 ohm or 120π.
b
See lessExplanation: The intrinsic impedance is the impedance of a particular material. It is the ratio of square root of the permeability to permittivity. For air, the intrinsic impedance is 377 ohm or 120π.
Which of the following is the correct relation between wavelength and the phase constant of a wave?
a Explanation: The phase constant is the ratio of 2π to the wavelength λ. Thus β = 2π/λ is the correct relation.
a
See lessExplanation: The phase constant is the ratio of 2π to the wavelength λ. Thus β = 2π/λ is the correct relation.
Calculate the velocity of a wave with frequency 2 x109 rad/s and phase constant of 4 x 108 units.
b Explanation: The velocity of a wave is the ratio of the frequency to the phase constant. Thus V = ω/β. On substituting the given values, we get V = 2 x109/ 4 x 108 = 5 units.
b
See lessExplanation: The velocity of a wave is the ratio of the frequency to the phase constant.
Thus V = ω/β. On substituting the given values, we get V = 2 x109/ 4 x 108 = 5 units.
For a lossless dielectric, the attenuation will be
b Explanation: The attenuation is the loss of power of the wave during its propagation. In a lossless dielectric, the loss of power will not occur. Thus the attenuation will be zero.
b
See lessExplanation: The attenuation is the loss of power of the wave during its propagation. In a lossless dielectric, the loss of power will not occur. Thus the attenuation will be zero.
Calculate the phase constant of a wave with frequency 12 rad/s and velocity 3×108 m/s(in 10-8 order)
c Explanation: The phase constant is given by β = ω√(με), where ω is the frequency in rad/s and 1/√(με) is the velocity of wave. On substituting √(με) = 3×108 and ω = 12, we get β = 12/(3×108) = 4 x 10-8m/s.
c
See lessExplanation: The phase constant is given by β = ω√(με), where ω is the frequency in
rad/s and 1/√(με) is the velocity of wave. On substituting √(με) = 3×108 and ω = 12, we get β = 12/(3×108) = 4 x 10-8m/s.
For a perfect dielectric, which parameter will be zero?
a Explanation: The conductivity will be minimum for a dielectric. For a perfect dielectric,the conductivity will be zero.
a
See lessExplanation: The conductivity will be minimum for a dielectric. For a perfect dielectric,the conductivity will be zero.
For a dielectric, the condition to be satisfied is
b Explanation: In a dielectric, the conductivity will be very less. Thus the loss tangent will be less than unity. This implies σ/ωε < 1 is true.
b
See lessExplanation: In a dielectric, the conductivity will be very less. Thus the loss tangent will be less than unity. This implies σ/ωε < 1 is true.
The intrinsic angle of the wave with a loss angle of 60 is
d Explanation: The angle of the loss tangent δ is twice the intrinsic angle θn. Thus tan δ = tan 2θn. We get θn = δ/2 = 60/2 = 30 degrees.
d
See lessExplanation: The angle of the loss tangent δ is twice the intrinsic angle θn. Thus tan δ = tan 2θn. We get θn = δ/2 = 60/2 = 30 degrees.