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SMTP connections secured by SSL are known as
SMTP connections secured by SSL are known as SMTPS.
SMTP connections secured by SSL are known as SMTPS.
See lessSMTP connections secured by SSL are known as
SMTP connections secured by SSL are known as SMTPS.
SMTP connections secured by SSL are known as SMTPS.
See lessIn electric fields, D= ε E. The correct expression which is analogous in magnetic fields will be
In magnetic fields, the analogous expression to (D = varepsilon E) in electric fields is (B = mu H), where:- (B) is the magnetic flux density (or magnetic induction),- (mu) is the magnetic permeability of the medium,- (H) is the magnetic field intensity.
In magnetic fields, the analogous expression to (D = varepsilon E) in electric fields is (B = mu H), where:
– (B) is the magnetic flux density (or magnetic induction),
– (mu) is the magnetic permeability of the medium,
– (H) is the magnetic field intensity.
See lessFind the current in a conductor with resistance 2 ohm, electric field 2 units and distance 100cm.
To find the current in a conductor, we typically either use Ohm's Law, which is (I = frac{V}{R}) (where (I) is the current, (V) is the potential difference, and (R) is the resistance), or we consider the relationship involving the electric field if the necessary variables for Ohm's Law aren't directRead more
To find the current in a conductor, we typically either use Ohm’s Law, which is (I = frac{V}{R}) (where (I) is the current, (V) is the potential difference, and (R) is the resistance), or we consider the relationship involving the electric field if the necessary variables for Ohm’s Law aren’t directly provided.
Given:
– Resistance ((R)) = 2 ohms,
– Electric field ((E)) = 2 units (assuming standard SI units, this would be 2 N/C, as electric field strength is typically measured in newtons per coulomb or volts per meter),
– Distance ((l)) = 100 cm = 1 meter (since 100 cm = 1 m, for consistency in SI units).
First, we need to ascertain the relationship between the electric field ((E)), the distance ((l)), and how we might derive the potential difference ((V)) from these, because (V = E times l) in a uniform electric field.
Given:
[E = 2 , text{N/C}]
[l = 1 , text{m}]
[V = E times l = 2 , text{N/C} times 1 , text{m} = 2 , text{V}]
Now, applying Ohm’s Law
See lessFind the current density of a material with resistivity 20 units and electric field intensity 2000 units.
To find the current density ((J)) of a material, you can use the relation between the current density, the electric field intensity ((E)), and the resistivity ((rho)) of the material. This relationship is given by Ohm's law in differential form as:[ J = frac{E}{rho} ]Given:- Resistivity, (rho = 20 ,Read more
To find the current density ((J)) of a material, you can use the relation between the current density, the electric field intensity ((E)), and the resistivity ((rho)) of the material. This relationship is given by Ohm’s law in differential form as:
[ J = frac{E}{rho} ]
Given:
– Resistivity, (rho = 20 , text{units})
– Electric field intensity, (E = 2000 , text{units})
Substitute the given values into the equation:
[ J = frac{2000}{20} ]
[ J = 100 , text{units of current density} ]
Therefore, the current density of the material is (100) units.
See lessFind the current density of a material with resistivity 20 units and electric field intensity 2000 units.
To find the current density (J) of a material, we can use the relation given by Ohm's law in a differential form which relates the electric field (E) to the current density (J) through the material's resistivity (rho). The formula is given by:[ J = frac{E}{rho} ]Given:- The resistivity (rho = 20) unRead more
To find the current density (J) of a material, we can use the relation given by Ohm’s law in a differential form which relates the electric field (E) to the current density (J) through the material’s resistivity (rho). The formula is given by:
[ J = frac{E}{rho} ]
Given:
– The resistivity (rho = 20) units
– The electric field intensity (E = 2000) units
By substituting the given values into the formula, we get:
[ J = frac{2000}{20} = 100 ]
Therefore, the current density (J) of the material is (100) units.
See lessFind the inductance of a coil with permeability 3.5, turns 100 and length 2m. Assume the area to be thrice the length.
To find the inductance (L) of a coil, we can use the formula:[L = frac{{N^2 mu A}}{l}]Where:- (L) is the inductance in Henrys (H),- (N) is the number of turns,- (mu) is the permeability of the core material in Henrys per meter (H/m),- (A) is the cross-sectional area in square meters (m(^2)),- (l) isRead more
To find the inductance (L) of a coil, we can use the formula:
[L = frac{{N^2 mu A}}{l}]
Where:
– (L) is the inductance in Henrys (H),
– (N) is the number of turns,
– (mu) is the permeability of the core material in Henrys per meter (H/m),
– (A) is the cross-sectional area in square meters (m(^2)),
– (l) is the length of the coil in meters (m).
From the given information:
– Permeability (mu = 3.5) H/m,
– Turns (N = 100),
– Length (l = 2) m,
– Area (A) is thrice the length, so assuming the question intends for area to be calculated based linearly off the length which seems a bit unclear, but typically area calculation would not directly use linear length in this manner. Since the area is described as “thrice the length,” a clarification on this context is needed for precise calculation.
However, to proceed with an assumption for the sake of calculation—assuming the information means that the total area is three times some dimension associated with the length—which isn’t standard. Let’s assume it intended that the cross-sectional dimension is somehow directly proportional to the length in a manner that would allow us to calculate an area that is three times a length attribute
See lessWhich of the following is an example of user agents for e-mail?
Microsoft Outlook
Microsoft Outlook
See lessThe resistance of a material with conductivity 2millimho/m2 , length 10m and area 50m is
To find the resistance of a material, we use the formula:[ R = frac{L}{sigma A} ]where ( R ) is the resistance in ohms (( Omega )), ( L ) is the length of the material in meters (m), ( sigma ) is the conductivity in siemens per meter (S/m), and ( A ) is the cross-sectional area in square meters (( mRead more
To find the resistance of a material, we use the formula:
[ R = frac{L}{sigma A} ]
where ( R ) is the resistance in ohms (( Omega )), ( L ) is the length of the material in meters (m), ( sigma ) is the conductivity in siemens per meter (S/m), and ( A ) is the cross-sectional area in square meters (( m^2 )). Given that conductivity is provided in millimhos per square meter, we first need to convert it to siemens per meter (S/m). Note that 1 mho is equivalent to 1 siemens (S), and therefore 1 millimho = ( 1 times 10^{-3} ) S.
Given values:
– Conductivity (( sigma )) = 2 millimhos/m(^2) = ( 2 times 10^{-3} ) S/m(^2)
– Length (( L )) = 10 m
– Cross-sectional area (( A )) = 50 m(^2)
Substituting the values into the formula:
[ R = frac{10}{(2 times 10^{-3}) times 50} ]
[ R = frac{10}{0.1} ]
[ R = 100 , Omega ]
Therefore, the resistance of the material
See lessThe resistance of a material with conductivity 2millimho/m2 , length 10m and area 50m is
To find the resistance of a material, we can use the formula derived from Ohm's Law, which relates resistance (R), resistivity (ρ), length (L), and cross-sectional area (A). However, in this context, we are given conductivity (σ) instead of resistivity (ρ). Conductivity is the inverse of resistivityRead more
To find the resistance of a material, we can use the formula derived from Ohm’s Law, which relates resistance (R), resistivity (ρ), length (L), and cross-sectional area (A). However, in this context, we are given conductivity (σ) instead of resistivity (ρ). Conductivity is the inverse of resistivity, thus:
[ sigma = frac{1}{rho} ]
The given values are:
– Conductivity, ( sigma = 2 ) millimhos/m ( = 2 times 10^{-3} ) S/m (since 1 mho = 1 S (Siemens), and 1 millimho = ( 10^{-3} ) S)
– Length, ( L = 10 ) m
– Cross-sectional area, ( A = 50 ) m(^2)
The resistance (R) of a material is calculated from resistivity (( rho )), length (L), and area (A) using the formula:
[ R = frac{rho cdot L}{A} ]
Given that ( sigma = frac{1}{rho} ), we can rearrange this to find ( rho = frac{1}{sigma} ), then substitute ( rho ) in the resistance formula:
[ R = frac{L}{sigma cdot A} ]
Substituting the
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