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The average gate power dissipation for an SCR is 0.5 Watts the voltage applied to the gate is Vg = 10 V. What is the maximum value of current Ig for safe operation
To find the maximum value of the gate current ( I_g ) for safe operation of the SCR given the power dissipation and the voltage applied to the gate, we can use the formula for power:[P = V_g cdot I_g]Where:- ( P ) is the power (0.5 Watts),- ( V_g ) is the voltage applied to the gate (10 V),- ( I_g )Read more
To find the maximum value of the gate current ( I_g ) for safe operation of the SCR given the power dissipation and the voltage applied to the gate, we can use the formula for power:
[
P = V_g cdot I_g
]
Where:
– ( P ) is the power (0.5 Watts),
– ( V_g ) is the voltage applied to the gate (10 V),
– ( I_g ) is the current through the gate.
We can rearrange this formula to solve for ( I_g ):
[
I_g = frac{P}{V_g}
]
Substituting the given values:
[
I_g = frac{0.5 , text{W}}{10 , text{V}} = 0.05 , text{A}
]
Therefore, the maximum value of the gate current ( I_g ) for safe operation is 0.05 A or 50 mA.
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