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  1. Asked: August 10, 2024In: Education

    Direct costs are also known as:

    Quearn
    Quearn Quearnist
    Added an answer on August 27, 2024 at 3:15 pm

    Direct costs are also known as variable costs or costs of goods sold (COGS).

    Direct costs are also known as variable costs or costs of goods sold (COGS).

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      • 0
  2. Asked: August 10, 2024In: Education

    Management accounting is said to meet:

    Quearn
    Quearn Quearnist
    Added an answer on August 27, 2024 at 3:14 pm

    Management accounting is said to meet the needs of management by providing timely and relevant financial and non-financial information for decision-making, planning, control, and performance evaluation. It helps in budgeting, forecasting, and analyzing financial performance to ensure that organizatiRead more

    Management accounting is said to meet the needs of management by providing timely and relevant financial and non-financial information for decision-making, planning, control, and performance evaluation. It helps in budgeting, forecasting, and analyzing financial performance to ensure that organizational goals are met.

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      • 0
  3. Asked: August 27, 2024In: Education

    The energy stored in an inductor 2H and current 4A is

    Quearn
    Quearn Quearnist
    Added an answer on August 27, 2024 at 3:13 pm

    The energy (W) stored in an inductor can be calculated using the formula:[ W = frac{1}{2} L I^2 ]where:- ( W ) is the energy in joules,- ( L ) is the inductance in henries,- ( I ) is the current in amperes.Given that ( L = 2H ) and ( I = 4A ):[ W = frac{1}{2} times 2 times 4^2 ][ W = frac{1}{2} timeRead more

    The energy (W) stored in an inductor can be calculated using the formula:

    [ W = frac{1}{2} L I^2 ]

    where:

    – ( W ) is the energy in joules,

    – ( L ) is the inductance in henries,

    – ( I ) is the current in amperes.

    Given that ( L = 2H ) and ( I = 4A ):

    [ W = frac{1}{2} times 2 times 4^2 ]

    [ W = frac{1}{2} times 2 times 16 ]

    [ W = frac{1}{2} times 32 ]

    [ W = 16 , text{joules} ]

    So, the energy stored in the inductor is 16 joules.

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  4. Asked: August 10, 2024In: Education

    Direct labour costs will include……………

    Quearn
    Quearn Quearnist
    Added an answer on August 27, 2024 at 3:12 pm

    Direct labour costs will include wages, salaries, and benefits for employees who are directly involved in the production of goods or services. This includes costs associated with workers who are physically creating a product or delivering a service.

    Direct labour costs will include wages, salaries, and benefits for employees who are directly involved in the production of goods or services. This includes costs associated with workers who are physically creating a product or delivering a service.

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  5. Asked: August 25, 2024In: Education

    What is the symbol used for the number of turns in the secondary winding?

    Quearn
    Quearn Quearnist
    Added an answer on August 27, 2024 at 3:10 pm

    The symbol used for the number of turns in the secondary winding is typically represented as ( N_s ).

    The symbol used for the number of turns in the secondary winding is typically represented as ( N_s ).

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  6. Asked: August 25, 2024In: Education

    What is the symbol used for the resistance referred to HV winding?

    Quearn
    Quearn Quearnist
    Added an answer on August 27, 2024 at 3:09 pm

    The symbol used for the resistance referred to the HV (High Voltage) winding is typically represented as ( R_{HV} ).

    The symbol used for the resistance referred to the HV (High Voltage) winding is typically represented as ( R_{HV} ).

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  7. Asked: August 27, 2024In: Education

    The Stoke’s theorem can be used to find which of the following?

    Quearn
    Quearn Quearnist
    Added an answer on August 27, 2024 at 3:06 pm

    Stoke's theorem can be used to find the relationship between the surface integral of the curl of a vector field over a surface and the line integral of the vector field over the boundary of that surface. Specifically, it can help in calculating circulation or flux in vector fields, linking the diffeRead more

    Stoke’s theorem can be used to find the relationship between the surface integral of the curl of a vector field over a surface and the line integral of the vector field over the boundary of that surface. Specifically, it can help in calculating circulation or flux in vector fields, linking the differential form (curl) to the integral form (line integral).

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  8. Asked: August 27, 2024In: Education

    Find the value of Stoke’s theorem for A = x i + y j + z k. The state of the function will be

    Quearn
    Quearn Quearnist
    Added an answer on August 27, 2024 at 3:04 pm

    To apply Stokes' Theorem for the vector field (mathbf{A} = x mathbf{i} + y mathbf{j} + z mathbf{k}), we need to compute the curl of (mathbf{A}) and the line integral of (mathbf{A}) around a closed curve that bounds a surface. 1. Calculate the curl (nabla times mathbf{A}):[nabla times mathbf{A} = begRead more

    To apply Stokes’ Theorem for the vector field (mathbf{A} = x mathbf{i} + y mathbf{j} + z mathbf{k}), we need to compute the curl of (mathbf{A}) and the line integral of (mathbf{A}) around a closed curve that bounds a surface.

    1. Calculate the curl (nabla times mathbf{A}):

    [

    nabla times mathbf{A} = begin{vmatrix}

    mathbf{i} & mathbf{j} & mathbf{k} \

    frac{partial}{partial x} & frac{partial}{partial y} & frac{partial}{partial z} \

    x & y & z

    end{vmatrix}

    ]

    Calculating this determinant:

    [

    nabla times mathbf{A} = mathbf{i}left(frac{partial z}{partial y} – frac{partial y}{partial z}right) – mathbf{j}left(frac{partial z}{partial x} – frac{partial x}{partial z}right) + mathbf{k}left(frac{partial y}{partial x} – frac{partial x}{partial y}right)

    ]

    Evaluating the partial derivatives, we get:

    [

    nabla times mathbf{A} = 0

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  9. Asked: August 27, 2024In: Education

    The Stoke’s theorem uses which of the following operation?

    Quearn
    Quearn Quearnist
    Added an answer on August 27, 2024 at 3:01 pm

    Stoke’s theorem uses the operation of integration—specifically, it relates a surface integral over a surface ( S ) to a line integral over the boundary ( partial S ) of that surface. The mathematical formulation is:[iint_S (nabla times mathbf{F}) cdot dmathbf{S} = oint_{partial S} mathbf{F} cdot dmaRead more

    Stoke’s theorem uses the operation of integration—specifically, it relates a surface integral over a surface ( S ) to a line integral over the boundary ( partial S ) of that surface. The mathematical formulation is:

    [

    iint_S (nabla times mathbf{F}) cdot dmathbf{S} = oint_{partial S} mathbf{F} cdot dmathbf{r}

    ]

    where ( mathbf{F} ) is a vector field, ( nabla times mathbf{F} ) is the curl of ( mathbf{F} ), ( dmathbf{S} ) is a differential area vector on the surface, and ( dmathbf{r} ) is a differential line element along the boundary.

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  10. Asked: August 27, 2024In: Education

    Find the value of Stoke’s theorem for y i + z j + x k.

    Quearn
    Quearn Quearnist
    Added an answer on August 27, 2024 at 3:00 pm

    To apply Stokes' Theorem to the vector field F = y i + z j + x k, we first need to understand that Stokes' Theorem relates a surface integral over a surface S to a line integral around the boundary curve C of that surface.The theorem states:[int_C mathbf{F} cdot dmathbf{r} = iint_S (nabla times mathRead more

    To apply Stokes’ Theorem to the vector field F = y i + z j + x k, we first need to understand that Stokes’ Theorem relates a surface integral over a surface S to a line integral around the boundary curve C of that surface.

    The theorem states:

    [

    int_C mathbf{F} cdot dmathbf{r} = iint_S (nabla times mathbf{F}) cdot dmathbf{S}

    ]

    1. Calculate the curl of F***:

    [

    nabla times mathbf{F} = begin{vmatrix}

    mathbf{i} & mathbf{j} & mathbf{k} \

    frac{partial}{partial x} & frac{partial}{partial y} & frac{partial}{partial z} \

    y & z & x

    end{vmatrix}

    ]

    Compute the determinant:

    [

    = mathbf{i}left(frac{partial x}{partial y} – frac{partial z}{partial z}right) – mathbf{j}left(frac{partial x}{partial x} – frac{partial y}{partial z}right) + mathbf{k}left(frac{partial z}{partial x} – frac

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1 … 155 156 157 158 159 … 305

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