Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
In case of TRC (Time Ratio Control), _________ is varied
In case of TRC (Time Ratio Control), the time ratio is varied.
In case of TRC (Time Ratio Control), the time ratio is varied.
See lessWhen the p-n junction diode is forward biased, the width of the depletion region
The width of the depletion region decreases when the p-n junction diode is forward biased.
The width of the depletion region decreases when the p-n junction diode is forward biased.
See lessA step down chopper has Vs = 230 V and R = 10 Ω. For a duty cycle of 0.4, the power taken by the chopper is 2097 Watts. Find the chopper efficiency. Take the voltage drop across the chopper switch as 2 V
To find the chopper efficiency, we can use the formula for efficiency (η) of a chopper:[eta = frac{P_{out}}{P_{in}} times 100%]where:- ( P_{out} ) is the output power,- ( P_{in} ) is the input power. 1. Calculate the output power ( P_{out} ):The power taken by the chopper is given as 2097 Watts. TheRead more
To find the chopper efficiency, we can use the formula for efficiency (η) of a chopper:
[
eta = frac{P_{out}}{P_{in}} times 100%
]
where:
– ( P_{out} ) is the output power,
– ( P_{in} ) is the input power.
1. Calculate the output power ( P_{out} ):
The power taken by the chopper is given as 2097 Watts. Therefore, ( P_{out} = 2097 , W ).
2. Calculate the input power ( P_{in} ):
The input voltage ( V_s ) is 230 V, and the duty cycle ( D ) is 0.4. First, calculate the average output voltage across the load:
[
V_{out} = D times V_s = 0.4 times 230 , V = 92 , V
]
The current ( I ) through the load can be calculated using Ohm’s law:
[
I = frac{V_{out}}{R} = frac{92 , V}{10 , Omega} = 9.2 , A
]
The output power can also be calculated as:
[
P_{out} = V_{out} times
See lessThe average gate power dissipation for an SCR is 0.5 Watts the voltage applied to the gate is Vg = 10 V. What is the maximum value of current Ig for safe operation?
To find the maximum value of the gate current ( I_g ) for safe operation of the SCR, we can use the formula for power dissipation:[P = V_g times I_g]Where:- ( P ) is the power dissipation (0.5 Watts),- ( V_g ) is the gate voltage (10 V),- ( I_g ) is the gate current.Rearranging the formula to solveRead more
To find the maximum value of the gate current ( I_g ) for safe operation of the SCR, we can use the formula for power dissipation:
[
P = V_g times I_g
]
Where:
– ( P ) is the power dissipation (0.5 Watts),
– ( V_g ) is the gate voltage (10 V),
– ( I_g ) is the gate current.
Rearranging the formula to solve for ( I_g ):
[
I_g = frac{P}{V_g}
]
Substituting the known values:
[
I_g = frac{0.5 text{ W}}{10 text{ V}} = 0.05 text{ A} = 50 text{ mA}
]
Thus, the maximum value of current ( I_g ) for safe operation is 50 mA.
See lessFind the output voltage for a step-up chopper when it is operated at a duty cycle of 50 % and Vs = 240 V.
To find the output voltage (( V_{out} )) for a step-up (boost) chopper, we can use the formula:[V_{out} = frac{V_s}{1 - D}]Where:- ( V_s ) is the input voltage,- ( D ) is the duty cycle (in decimal form).Given:- ( V_s = 240 , V )- ( D = 50% = 0.5 )Substituting the values in:[V_{out} = frac{240}{1 -Read more
To find the output voltage (( V_{out} )) for a step-up (boost) chopper, we can use the formula:
[
V_{out} = frac{V_s}{1 – D}
]
Where:
– ( V_s ) is the input voltage,
– ( D ) is the duty cycle (in decimal form).
Given:
– ( V_s = 240 , V )
– ( D = 50% = 0.5 )
Substituting the values in:
[
V_{out} = frac{240}{1 – 0.5} = frac{240}{0.5} = 480 , V
]
Therefore, the output voltage for the step-up chopper is 480 V.
See lessLatching current for an SCR is 100 mA, DC source of 200 V is also connected from the SCR to the L load. Compute the minimum width of the gate pulse required to turn on the device. Take L = 0.2 H
To calculate the minimum width of the gate pulse required to turn on the SCR, we can use the formula that relates the latching current (I_L), the inductance (L), and the applied voltage (V) to find the energy required to turn on the device. 1. The latching current (I_L) is given as 100 mA or 0.1 A.Read more
To calculate the minimum width of the gate pulse required to turn on the SCR, we can use the formula that relates the latching current (I_L), the inductance (L), and the applied voltage (V) to find the energy required to turn on the device.
1. The latching current (I_L) is given as 100 mA or 0.1 A.
2. The inductance (L) is given as 0.2 H.
3. The applied voltage (V) is 200 V.
To find the minimum width of the gate pulse (t), we first need to compute the time constant of the inductor using the formula:
[
V = L frac{dI}{dt}
]
Rearranging the formula gives us:
[
dt = frac{L}{V} dI
]
Now, we integrate it from 0 to (I_L) (0 to 0.1 A):
[
t = int_0^{I_L} frac{L}{V} dI = frac{L}{V} I_L
]
Substituting the known values:
[
t = frac{0.2 , text{H}}{200 , text{V}} cdot 0.1 , text{A}
]
[
t = frac{0.2}{200} cd
See lessIn a step down chopper, if Vs = 100 V and the chopper is operated at a duty cycle of 75 %. Find the output voltage.
To find the output voltage (Vo) in a step-down chopper, you can use the formula:[ Vo = Vs times D ]where Vs is the input voltage and D is the duty cycle (as a decimal). Given:- Vs = 100 V- D = 75% = 0.75Now, substituting the values into the formula:[ Vo = 100 V times 0.75 = 75 V ]So, the output voltRead more
To find the output voltage (Vo) in a step-down chopper, you can use the formula:
[ Vo = Vs times D ]
where Vs is the input voltage and D is the duty cycle (as a decimal). Given:
– Vs = 100 V
– D = 75% = 0.75
Now, substituting the values into the formula:
[ Vo = 100 V times 0.75 = 75 V ]
So, the output voltage is 75 V.
See lessFind the output voltage expression for a step down chopper with Vs as the input voltage and α as the duty cycle.
The output voltage ( V_o ) expression for a step-down chopper (also known as a buck converter) can be derived from the relationship between the input voltage ( V_s ), the duty cycle ( alpha ), and the output voltage.For a step-down chopper, the output voltage is given by:[V_o = alpha V_s]Where:- ( VRead more
The output voltage ( V_o ) expression for a step-down chopper (also known as a buck converter) can be derived from the relationship between the input voltage ( V_s ), the duty cycle ( alpha ), and the output voltage.
For a step-down chopper, the output voltage is given by:
[
V_o = alpha V_s
]
Where:
– ( V_o ) = Output voltage
– ( V_s ) = Input voltage
– ( alpha ) = Duty cycle (percentage of time the switch is on, expressed as a fraction between 0 and 1)
So the output voltage is directly proportional to the duty cycle and the input voltage.
See lessIf T is the time period for a chopper circuit and α is its duty cycle, then the chopping frequency is
The chopping frequency ( f ) of a chopper circuit can be calculated using the formula:[f = frac{1}{T}]where ( T ) is the time period of the chopper circuit. The duty cycle ( alpha ) is defined as the ratio of the on-time to the total time period, but does not directly affect the chopping frequency iRead more
The chopping frequency ( f ) of a chopper circuit can be calculated using the formula:
[
f = frac{1}{T}
]
where ( T ) is the time period of the chopper circuit. The duty cycle ( alpha ) is defined as the ratio of the on-time to the total time period, but does not directly affect the chopping frequency itself. Therefore, the chopping frequency is inversely proportional to the time period.
So, to summarize:
[
f = frac{1}{T}
]
See lessLatching current for an SCR is 100 mA, a dc source of 200 V is also connected to the SCR which is supplying an R-L load. Compute the minimum width of the gate pulse required to turn on the device. Take L = 0.2 H & R = 20 ohm both in series
To compute the minimum width of the gate pulse required to turn on an SCR given the parameters:- Latching current (I_L) = 100 mA = 0.1 A- DC Source Voltage (V) = 200 V- Inductance (L) = 0.2 H- Resistance (R) = 20 Ω 1. Determine the time constant (τ):The time constant (τ) for an RL circuit is given bRead more
To compute the minimum width of the gate pulse required to turn on an SCR given the parameters:
– Latching current (I_L) = 100 mA = 0.1 A
– DC Source Voltage (V) = 200 V
– Inductance (L) = 0.2 H
– Resistance (R) = 20 Ω
1. Determine the time constant (τ):
The time constant (τ) for an RL circuit is given by:
[
τ = frac{L}{R}
]
Substituting the given values:
[
τ = frac{0.2 , text{H}}{20 , Omega} = 0.01 , text{s} = 10 , text{ms}
]
2. Determine the voltage across the load:
The voltage across the load can be calculated using Ohm’s law:
[
V_R = I cdot R
]
In steady state, the maximum current (I) can be found from:
[
I = frac{V}{R} = frac{200 , V}{20 , Omega} = 10 , A
]
3. Get the required rise time to reach the latching current:
The current through the inductor can be expressed as:
See less